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TDBFS - Searching the Graph |
Wersja polska | English version |
For a given list of adjacent vertices of a graph and a chosen vertex v write down in the Depth First Search (DFS) or Breadth First Search (BFS) order all the vertices from the connected component of the graph containing v. Assume that the number of vertices of the graph is at most 1000.
Input
t [the number of graphs <= 100]
Graph:
n [1 <= n <= 1000 the number of graph vertices]
i m a b c ... [the list of m adjacent vertices to vertex i]
Any query is as follows: [not more than n queries]
v i
where 1 <= v <= n is the beginning vertex and i = 0 for DFS order and i = 1 for BFS order.
0 0 [at the end of the serie]
The list for isolated vertex a is a 0.
Output
graph i [test case, word graph is necessary]
a b c ... [the DFS or BFS order of all vertices]
Example
Input: 3 6 1 2 3 4 2 2 3 6 3 2 1 2 4 1 1 5 0 6 1 2 5 1 1 0 1 0 0 0 10 1 6 3 5 6 7 8 9 2 1 9 3 2 1 5 4 5 6 7 8 9 10 5 4 1 3 7 8 6 3 1 4 7 7 5 1 4 5 6 8 8 5 1 4 5 7 10 9 3 1 2 4 10 2 4 8 7 1 1 0 2 1 4 1 7 1 0 0 2 1 0 2 0 1 1 0 0 Output: graph 1 5 1 3 2 6 4 1 3 2 6 4 graph 2 7 1 4 5 6 8 3 9 10 2 1 3 5 7 4 6 8 10 9 2 2 9 1 4 3 5 6 7 8 10 4 6 7 8 9 10 1 5 2 3 7 1 4 5 6 8 3 9 10 2 graph 3 1
Added by: | mima |
Date: | 2004-10-22 |
Time limit: | 15s |
Source limit: | 5000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
hide comments
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2018-10-18 01:39:54
Good problem for those that are starting to solve BFS and DFS problem... Last edit: 2018-10-18 01:40:36 |
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2016-04-08 21:44:34 kamran siddique
1st Go :) |
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2016-03-08 17:26:30 Amir Najjar
AC on first submit Just make sure u visit the smaller indexed node first. |
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2016-03-02 20:26:38
may someone explain this prolbleù statment?? |
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2016-02-27 09:53:53 bourne
would any DFS solution not work? Do we necessarily need to order them according to input? |
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2015-12-07 11:16:07 Nehal J Wani
"[not more than n queries]" is a lie. |
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2015-10-16 17:18:19 hashem sllat
cake of piece :D |
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2015-07-03 20:41:01
This problem is not clear at all |
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2014-10-31 00:38:37 Kishlay Raj
in dfs its pushing the nodes in reverse order i.e. the one with higher value get pushed first |
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2014-10-31 00:38:37 LeppyR64
Use a preorder traversal. Order the edges on the order they are input. Last edit: 2011-11-25 16:22:25 |