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SUMPRO - SUM OF PRODUCT |
Given a number N, find the sum of all products x * y such that N / x = y (integer division).
Since the sum can be very large, please output this modulo 1000000007.
Input
The first line of input file contains an integer T, the number of test cases to follow. Each of the next T lines contain an integer N.
Output
Output T lines containing the answer to corresponding test case.
Example
Input: 3 2 4 6 Output: 4 15 33
Constraints:
1 ≤ T ≤ 500
1 ≤ N ≤ 109
Explanation
Case #1:
2 / 1 = 2
2 / 2 = 1
Answer = 1 * 2 + 2 * 1 = 4
Case #2:
4 / 1 = 4
4 / 2 = 2
4 / 3 = 1
4 / 4 = 1
Answer = 1 * 4 + 2 * 2 + 3 * 1 + 4 * 1 = 15
Added by: | ivar.raknahs |
Date: | 2015-01-23 |
Time limit: | 1s-1.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Own |
hide comments
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2016-02-29 17:02:13
how to fix errors time limit exceeded - java Last edit: 2016-02-29 19:50:07 |
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2016-01-12 23:09:13 Arpan Mukherjee
Thanks @anuj0503 :D your hints just made the day :p |
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2016-01-03 18:59:42
nice problem.. long long int is working fine |
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2015-12-15 13:41:44 Shubhransh Srivastav
use unsigned long long int... cost me a tle with long long despite using O(sqrt(n)) solution.... Last edit: 2015-12-15 13:42:21 |
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2015-12-11 08:10:44
HINT:1. If you divide a number say N, by any number less than N ( from 1 to N-1 ), the Quotient will be in range of 1 to sqrt(N). 2. All the Quotient repeat within range. |
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2015-12-05 10:06:27
o(sqrt(n)) with long long int AC:-) Last edit: 2015-12-05 10:06:56 |
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2015-11-28 16:56:01 bka
good question ;) |
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2015-10-12 17:06:54
can i check someone's else submission???plz tell how to achieve O(sqrt(n)) Last edit: 2015-10-12 17:21:46 |
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2015-08-22 12:12:51
nice !! Last edit: 2015-08-22 12:40:30 |
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2015-06-05 21:07:28 Abhay Jain
Got an AC! But time of 0.75. Trying to figure out how to optimize it better |