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RMQSQ - Range Minimum Query |
You are given a list of N numbers and Q queries. Each query is specified by two numbers i and j; the answer to each query is the minimum number between the range [i, j] (inclusive).
Note: the query ranges are specified using 0-based indexing.
Input
The first line contains N, the number of integers in our list (N <= 100,000). The next line holds N numbers that are guaranteed to fit inside an integer. Following the list is a number Q (Q <= 10,000). The next Q lines each contain two numbers i and j which specify a query you must answer (0 <= i, j <= N-1).
Output
For each query, output the answer to that query on its own line in the order the queries were made.
Example
Input: 3
1 4 1
2
1 1
1 2 Output: 4
1
Added by: | Joshua Kirstein |
Date: | 2014-10-18 |
Time limit: | 3s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
hide comments
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2018-02-26 13:45:45
0.01s using sqrt decomposition and segment tree, but 0.02s using sparse table! Last edit: 2018-02-28 16:06:26 |
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2018-01-13 00:19:28
[DELETED] Last edit: 2018-05-07 16:41:15 |
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2017-12-19 09:59:38
first sqrt decomposition :) |
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2017-08-25 19:03:24
0.01s Using Segment Tree |
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2017-08-23 16:36:06
AC in one go 0.3 secs ^_^ SQRT Decomposition Last edit: 2017-08-23 21:51:14 |
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2017-07-23 15:49:19
AC in one go took 0.59s , <JAVA>[*_*] :) |
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2017-05-26 11:21:17 shashank joshi
koi btayega ye code kyun wrong answer de rha hai ? <1. Don't post any source code here.> Last edit: 2017-05-26 12:19:42 |
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2017-05-25 15:52:41
this question can be done in 3 ways(i recommend trying all) 1.square root decomposition(mo's algorithm).(O(n*sqrt(n)) 2.sparse table.(O(n) 3.segment tree.O(nlogn). |
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2017-04-11 08:04:09 avidcoder
Dynamic programming approach with N^2 preprocessing using 2D array won't work |
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2016-11-15 11:14:47 Randomize
solved using modified BIT |