RETO10M4 - RETO 4 MARATON 10

Given a natural number n (1 <= n <= 500000), please output the summation of all its proper divisors. Definition: A proper divisor of a natural number is the divisor that is strictly less than the number.

e.g. number 20 has 5 proper divisors: 1, 2, 4, 5, 10, and the divisor summation is: 1 + 2 + 4 + 5 + 10 = 22.

Input

An integer stating the number of test cases (equal to about 200000), and that many lines follow, each containing one integer between 1 and 500000 inclusive.

Output

One integer each line: the divisor summation of the integer given respectively.

Example

Input:
3
2
10
20

Output:
1
8
22

Added by:MARATON AFDM
Date:2015-09-29
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64 GOSU JS-MONKEY

hide comments
2018-10-14 16:42:58
Statement copied 1:1 from DIVSUM, except that you have to print sum of divisors of number of testcases also. A moot point since this is what I got AC with:

print("1\n1\n8\n22")

I just can't even...
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