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PR003004 - Digit Sum |
For a pair of integers a and b, the digit sum of the interval [a, b] is defined as the sum of all digits occurring in all numbers between (and including) a and b. For example, the digit sum of [28, 31] can be calculated as:
2+8 + 2+9 + 3+0 + 3+1 = 28
Given the numbers a and b, calculate the digit sum of [a, b].
Input
On the first line one positive number: the number of test cases, at most 100.
After that per test case:
- one line with two space-separated integers, a and b (0 ≤ a ≤ b ≤ 1015).
Output
Per test case:
- one line with an integer: the digit sum of [a, b];
Example
Input: 3 0 10 28 31 1234 56789 Output: 46 28 1128600
Added by: | kojak_ |
Date: | 2013-11-25 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | BAPC |
hide comments
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2020-02-09 20:05:37
this problem have something rare. I have the same situation as dwij28, 3 comments below |
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2019-12-05 11:20:16
Hmm weird, I got WA for CRCRC1C, but got AC for this one with literally the same code. |
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2018-02-04 13:04:47 Akshay Aradhya
LOL I forgot to change my DP memory from CPCRC1C. Changed it and AC :) |
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2016-06-29 11:58:48
Answer should technically always fit in the range of long long int. But my C++ solution gives a WA but its exact 100% translation into python gives AC. Can someone tell me what could be the reason behind it ? |
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2016-01-23 19:22:45 nitin jain
just ctrl c and ctrl v !! CPRC1C |
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2016-01-23 19:18:37
copy paste CPCRC1C and got AC in one go......:-) |
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2015-07-04 17:01:24 Yash
CPCRC1C accepted but NZEC here :( |
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2013-11-28 05:39:02 fitcat
Same as CPCRC1C except with higher upper limit. |