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PARTY - Party Schedule |
You just received another bill which you cannot pay because you lack the money.
Unfortunately, this is not the first time to happen, and now you decide to investigate the cause of your constant monetary shortness. The reason is quite obvious: the lion's share of your money routinely disappears at the entrance of party localities.
You make up your mind to solve the problem where it arises, namely at the parties themselves. You introduce a limit for your party budget and try to have the most possible fun with regard to this limit.
You inquire beforehand about the entrance fee to each party and estimate how much fun you might have there. The list is readily compiled, but how do you actually pick the parties that give you the most fun and do not exceed your budget?
Write a program which finds this optimal set of parties that offer the most fun. Keep in mind that your budget need not necessarily be reached exactly. Achieve the highest possible fun level, and do not spend more money than is absolutely necessary.
Input
The first line of the input specifies your party budget and the number n of parties.
The following n lines contain two numbers each. The first number indicates the entrance fee of each party. Parties cost between 5 and 25 francs. The second number indicates the amount of fun of each party, given as an integer number ranging from 0 to 10.
The budget will not exceed 500 and there will be at most 100 parties. All numbers are separated by a single space.
There are many test cases. Input ends with 0 0.
Output
For each test case your program must output the sum of the entrance fees and the sum of all fun values of an optimal solution. Both numbers must be separated by a single space.
Example
Sample input: 50 10 12 3 15 8 16 9 16 6 10 2 21 9 18 4 12 4 17 8 18 9 50 10 13 8 19 10 16 8 12 9 10 2 12 8 13 5 15 5 11 7 16 2 0 0 Sample output: 49 26 48 32
Added by: | Patryk Pomykalski |
Date: | 2004-07-01 |
Time limit: | 3s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Swiss Olympiad in Informatics 2004 |
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2016-05-19 05:08:57
4 WA's for using short instead of int. A really basic problem for DP. Must do! :) |
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2016-05-01 14:33:46
Wrote the 1st code in 10 minutes and got a WA Realised it is asking for "Minimum Entrance fee" Hint : For MInimum Entrance fee = ask urself this question - Given a amount of fun, would u like to pay lesser money than the total money u had (as long as u dont make a buyoff with fun) ! |
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2016-04-26 18:14:15 Akshay Aradhya
OMG I feel so stupid I was using : int DP[501][101]; instead of : int DP[101][501]; |
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2016-04-23 20:27:18
More fun, less money--> Add it,, then you will get answer... AC in first Go. |
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2016-04-21 19:18:20
very good question to get started with knapsack |
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2016-04-12 23:59:46 Arpan Mukherjee
No need of backtracking,just print the dp table,you'll get the logic. simple 0/1 knapsack. |
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2016-04-07 12:42:01
A problem is only difficult until it is solved. A tweak after classical knapsack is all you need to solve this problem. :) |
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2016-02-14 14:52:16 SUBHAM SANGHAI
Tricky one..Finallly got AC .. thanku@linus for the test cases.... :) Last edit: 2016-02-14 14:52:43 |
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2016-02-14 11:29:12
note print the max fun we can get "with the minimum possible entrance fee". |
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2016-02-14 10:54:38 Linus
small variation in 0/1 knapsack below are all test cases mentioned in comments test cases : 7 2 6 1 5 1 40 5 12 10 16 10 20 10 24 10 8 3 20 1 25 6 7 2 5 1 6 1 0 0 output 5 1 36 23 0 0 5 1 |