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PARSUMS - Nonnegative Partial Sums |
You are given a sequence of n numbers a0 ... an−1. A cyclic shift by k positions (0 ≤ k ≤ n−1) results in the following sequence: ak, ak+1 ... an−1, a0, a1 ... ak−1. How many of the n cyclic shifts satisfy the condition that the sum of the first i numbers is greater than or equal to zero for all i with 1 ≤ i ≤ n?
Input
Each test case consists of two lines. The first contains the number n (1 ≤ n ≤ 106), the number of integers in the sequence. The second contains n integers a0 ... an−1 (−1000 ≤ ai ≤ 1000) representing the sequence of numbers. The input will finish with a line containing 0.
Output
For each test case, print one line with the number of cyclic shifts of the given sequence which satisfy the condition stated above.
Example
Input: 3 2 2 1 3 -1 1 1 1 -1 0 Output: 3 2 0
Problem setter: Adrian Kuegel
Added by: | David García Soriano |
Date: | 2011-11-26 |
Time limit: | 8.989s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Southwestern Europe Regional, SWERC 2011 |
hide comments
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2011-12-03 06:03:16 M@@Y@
@Raja .... its " How many of the n cyclic shifts " ...i guess i m making things clear. |
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2011-11-30 03:37:14 R@ja.... -[^_^]-
how come the output for 1st case is 3...will 0 shift not do..???? pl help.. Last edit: 2011-11-30 03:38:09 |
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2011-11-27 18:48:40 Kazi Rakibul Hossain
nice problem :) |