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PAIRS1 - Count the Pairs |
Given N integers [0 < N <= 10^5], count the total pairs of integers that have a difference of K. (Everything can be done with 32 bit integers).
Input
1st line contains integers N and K.
2nd line contains N integers of the set. All the N numbers are distinct.
Output
One integer - the number of pairs of numbers that have a difference of K.
Example
Input: 5 2 1 5 3 4 2 Output: 3
Input: 10 1 363374326 364147530 61825163 1073065718 1281246024 1399469912 428047635 491595254 879792181 1069262793 Output: 0
Added by: | psn |
Date: | 2013-10-18 |
Time limit: | 0.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own |
hide comments
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2019-01-04 17:01:31
Good Question To Apply Binary Search Last edit: 2019-01-04 17:01:48 |
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2018-08-27 08:27:34
all nos are not distinct |
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2018-08-17 22:17:07 DOT
I guess the test cases are weak, because I only employed sorting and compared the differences linearly in 2 loops, yet my code ran in 0.03s. |
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2017-07-14 21:03:33
Good Question :) |
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2017-06-28 18:18:40
AC in one go....good use of sorting and binary search |
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2017-06-23 13:43:01 Sigma Kappa
I've solved it in O(nlogn), basically for each position you do two binary searches. |
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2017-06-18 07:08:25
The problem is same as HACKRNDM |
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2017-02-11 06:20:34
nothing in the question,just use sets! |
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2016-12-28 14:54:45
AC in 1 Go.......!!! sorting,,,,binary search!!!! |
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2016-12-07 06:22:57
i am getting time limit excedded. i guess its O(n^2) solution only!! |