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ONP - Transform the Expression |
Transform the algebraic expression with brackets into RPN form (Reverse Polish Notation). Two-argument operators: +, -, *, /, ^ (priority from the lowest to the highest), brackets ( ). Operands: only letters: a, b ... z. Assume that there is only one RPN form (no expressions like a*b*c).
Input
t [the number of expressions <= 100] expression [length <= 400] [other expressions]
Text grouped in [ ] does not appear in the input file.
Output
The expressions in RPN form, one per line.
Example
Input: 3 (a+(b*c)) ((a+b)*(z+x)) ((a+t)*((b+(a+c))^(c+d))) Output: abc*+ ab+zx+* at+bac++cd+^*
Added by: | mima |
Date: | 2004-05-01 |
Time limit: | 5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS PERL6 VB.NET |
Resource: | - |
hide comments
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2016-08-13 18:15:49
test cases do not check for cases like a^b+c |
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2016-08-10 20:42:24
Please only solve using stack if coding in java c or c++ , DO NOT TRY STRING AND STRINGBUFFERS made it more complicated. find a RPN stack algo and implement it. At last I did it gives me happiness. |
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2016-08-08 15:04:09
AC on one go :) |
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2016-08-02 21:05:29
No need for a stack, although it's the best way. Take in count the operations listed, because the test cases don't include all of them. Cost me one WA. |
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2016-07-26 20:15:56
phew:):) |
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2016-07-13 09:48:07 Ashvjit Singh
if anyone is having any problem, I suggest you study about RPN. Very simple question with poor description. |
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2016-07-11 07:09:33
Good for learning stack... |
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2016-06-18 19:17:41
Stack 101 AC in one go!! |
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2016-06-16 23:44:51
as easy as stack can be :-P ....basic prob no issues !! already had the code :-) AC :-) |
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2016-06-11 09:14:55 candide
Easy and classical question, no trap. After multiple tries, AC in Python in 0.00s (observe that left parenthesis are useless). Problem description is unclear. |