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NOVICE25 - Problem 5 |
A natural number k is divisor of another natural number if K completely divides N, means N % k = 0. For example 6 has 4 positive divisors 1, 2, 3, and 6. Now given a natural number N you have to find number of its positive divisors.
Input
First line contains T the number of test cases. Each of next T lines contain one integer N. 1<=N<=10^9
Output
For each test case print the answer in a new line.
Example
Input: 2
6
7
Output: 4
2
Added by: | Mahesh Chandra Sharma |
Date: | 2011-01-26 |
Time limit: | 0.100s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | NSIT Noivce contest #2 |