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MPOW - Power of matrix |
You will be given a square matrix M and a positive integer power N. You will have to compute M raised to the power N. (that is, M multiplied with itself N times.)
Input
First line of input is T (number of test-cases) First line of each test-case contains two integer M and N, where M is size of square matrix that we have to exponent and N is the power to which we have to exponent it. The next M lines describe the input matrix. Each line contains exactly M elements corresponding to each array
Output
Output M line corresponding to each row of resultant matrix Each line must have M integers where jth element of ith line is jth element of resultant matrix taken modulo with 1000000007 (109+7).
Simply, you have to print the resultant square matrix.
Example
Input: 2 2 3 1 0 1 1 3 3 1 0 4 1 2 2 0 4 4 Output: 1 0 3 1 17 112 116 15 88 100 28 144 160
Constraints
1 ≤ T ≤ 10
1 ≤ M ≤ 50
1 ≤ N ≤ 100000
0 ≤ each element of input matrix ≤ 109
Added by: | ivar.raknahs |
Date: | 2014-12-19 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | own |
hide comments
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2023-10-07 15:20:31
Is anyone getting TLE with python? |
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2023-02-11 19:21:36
if anyone is here after watching the CodeNcode video do this in multiplication operator :- res[i][j] = (res[i][j] % mod + ((A[i][k] % mod) * (B[k][j] % mod) % mod)) % mod use #define mod 1000000007 and instead of int use long long int |
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2022-06-24 17:58:22
If anyone is having a problem with MOD, please check the addition and multiplication property of MOD. Use long long for 1000000007 and for 2D vector/array as well! |
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2022-01-25 06:00:59
may I know Why we have to use the mod for each element in the matrix. |
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2021-12-04 21:58:33
make sure to take mod during addition of elements in multiplication :) |
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2021-07-13 12:19:21
result[i][j]=(result[i][j]%mod+(I[i][k]%mod*A[k][j]%mod)%mod)%mod; use this for modular arithematics |
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2021-02-06 17:21:57
if anyone is here after watching the CodeNcode video do this in multiplication operator :- res[i][j] = (res[i][j] % mod + ((A[i][k] % mod) * (B[k][j] % mod) % mod)) % mod where mod = 1e9 + 7 And use long long int instead of int |
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2021-01-10 08:47:53
i am getting TLE ,even doing in O(m^3*logn) why?? |
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2020-12-02 14:52:35
- use fast exponentiation - use long long - use % mod for every + and * Last edit: 2020-12-02 15:45:36 |
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2020-11-13 11:23:57
I am doing in java and I followed code ncode's video still I am stuck at test case 7, and I am using long matrix not passing it by reference. Even then :( |