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LOPOV - Lopov |
The difficult economic situation in the country and reductions in government agricultural subsidy funding have caused Mirko to change his career again, this time to a thief. His first professional endeavour is a jewellery store heist.
The store contains N pieces of jewellery, and each piece has some mass Mi and value Vi. Mirko has K bags to store his loot, and each bag can hold some maximum mass Ci. He plans to store all his loot in these bags, but at most one jewellery piece in each bag, in order to reduce the likelihood of damage during the escape.
Find the maximum total jewellery value that Mirko can “liberate”.
Input
The first line of input contains two numbers, N and K (1 ≤ N, K ≤ 300 000).
Each of the following N lines contains a pair of numbers, Mi and Vi (1 ≤ Mi, Vi ≤ 1 000 000).
Each of the following K lines contains a number, Ci (1 ≤ Ci ≤ 100 000 000).
All numbers in the input are positive integers.
Output
The first and only line of output must contain the maximum possible total jewellery value.
Example
Input: 2 1 5 10 100 100 11 Output: 10
Input: 3 2 1 65 5 23 2 99 10 2 Output: 164
Added by: | Tomislav Babic |
Date: | 2013-10-12 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | COCI 2013 1. round |
hide comments
2023-09-16 08:37:16
Think of the test case where number of bags are greater than the number of jewelleries |
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2021-12-28 10:07:49
Nobody Wants your fucking Time Complexity Man ! |
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2016-07-10 16:32:18
AC O(nlogn + klogk) in 0.31 |
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2014-10-04 05:23:00 Pulkit Singhal
Easy One :) AC in O(nlogn+klogk) |
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2014-05-14 03:48:25 you_know_why
TLE for (nlogn+nlogk) !!! |
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2014-04-05 17:53:15 785227
Go greedy !! |
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2013-12-27 20:59:23 Dario Sindicic
my 100th solved problem |