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LEAF - Leaf |
A leaf is inscribed in a square. Given the length of a side of the square. Find the area of the leaf.
A leaf is the intersection of two quarter circles drawn from two opposite ends of a square, with the radius being equal to the length of a side of the square.
Input
In the first line there will be an integer t (t ≤ 105) the number of testcases. Next t lines will contain a number a (0 ≤ a ≤ 106), the side length of the square.
Output
Print the area of the Leaf. Errors less than 10-6 will be ignored.
Example
Input: 2
1
2
Output: 0.5707963268
2.2831853072
| Added by: | Rezwan |
| Date: | 2016-05-13 |
| Time limit: | 1s |
| Source limit: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Languages: | All except: ASM64 GOSU JS-MONKEY |
hide comments
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2016-05-14 16:14:32 [Rampage] Blue.Mary
My IO: 1 1000000 Output: 570796326794.89661923132169163975 If the judge solution can't get .896619 after the floating point, then the judge solution must be wrong. Even if Pi = 2 * acos(0), you can not assume (in C++) double pi = 2 * acos(double(0)). Even long double has precision problem. Last edit: 2016-05-14 16:18:18 |
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2016-05-14 10:56:25
@abhi2296 use PI = 2*acos(0) |
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2016-05-14 10:27:20
Id:16913391 Can u please check? Getting wrong answer EDIT: AC!!! Last edit: 2016-05-14 11:20:13 |
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2016-05-14 09:14:29
There is a very little tricky case... If you can't find it; you'll get RTE :P ... But If you can find this, don't post it here. :) There is nothing wrong with the Judge Data. :) Last edit: 2016-05-14 09:14:49 |
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2016-05-14 09:12:54
Python will get RTE... :P For a tricky case. :) |
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2016-05-14 07:39:33
Shows runtime error, please check |
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2016-05-14 05:34:11 [Rampage] Blue.Mary
To this kind of problem, the author should use a (self-constructed) judge "Ignore absolute or relative errors less than 10^-9". |
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