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LABYR2 - Number Labyrinth |
Fred is a robotic mouse built by a group of students of artificial intelligence. Fred can move around in the labyrinth shown in the picture below. Whenever Fred comes to a place marked by a number, he has to choose one of the possible directions. Behavior of the mouse should look chaotic and complex enough so that it will impress students' supervisor.
+--------4 | | | 8--9 | | | | | 2--7--0 | | | | 1 6-----+
Numbered places in the labyrinth are called nodes. Fred has one integer X stored in its memory and can perform some calculations. In each node (except node 1) he chooses a direction according to X, decreases X by 1 and goes to the chosen node. The direction is chosen according to this rules:
Node 2: Compute X mod 3. If the result is 0, go to 7 1, go to 1 2, go to 4. Node 4: Let Y be X written backwards (in decimal system). If Y>X then go to 6 otherwise go to 2. Node 6: Compute the number of digits of X (in decimal system). If the result is even then go to 4 otherwise go to 7. Node 7: Compute (X*X) mod 7. If the result is 0 go to 2 1 go to 6 2 go to 8 4 go to 0. Node 8: Compute X mod 5. If the result is 2 or 3 then go to 7 otherwise go to 9. Node 9: If you have come from 8 then go to 0. If you have come from 0 then go to 8. Node 0: Let Y be the third least significant digit of X in decimal system (if X<100 then Y=0). If Y<=7 then go to 7 otherwise go to 9.
At the beginning of each experiment, the experimenter puts the mouse in the node 0 and initializes value X by voice. After that, the mouse starts to move. The mouse displays current value of X on its digital display. The experiment finishes when the mouse enters the node 1, the result of the experiment is the number displayed. If the value of X decreases to zero, the experiment fails and its result is -1.
Input
The input contains several initial values of X (less than two-million) as they were told by the experimenter.
Output
For each value of X in the input write to a separate line of the output the result of the corresponding experiment (see example output).
Example
Input: thirteen fourteen one-thousand one-million-three-hundred-and-twenty-five-thousand-nine-hundred-and-seventy-nine Output: -1 9 789 1325784
Note: New test cases were added. Thanks to Robert Gerbicz and Stephen Merriman's discussion in the forum.
Added by: | Fudan University Problem Setters |
Date: | 2007-12-01 |
Time limit: | 0.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: C99 ERL GOSU JS-RHINO |
Resource: | IPSC 1999 |
hide comments
2022-06-15 17:28:37 David
No catch. Run the simulation. |
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2014-11-14 03:34:54 Balakrishnan B
Is there any catch in the problem or just bruteforce? |
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2010-01-01 05:01:44 Vijay
Use "forty" for 40 Last edit: 2010-01-01 08:15:18 |