KQUERYO - K-Query Online

Given a sequence of n numbers a1, a2, ..., an and a number of k-queries. A k-query is a triple (i, j, k) (1 ≤ i ≤ j ≤ n). For each k-query (i, j, k), you have to return the number of elements greater than k in the subsequence ai, ai+1, ..., aj.

Input

  • Line 1: n (1 ≤ n ≤ 30000).
  • Line 2: n numbers a1, a2, ..., an (1 ≤ ai ≤ 109).
  • Line 3: q (1 ≤ q ≤ 200000), the number of k- queries.
  • In the next q lines, each line contains 3 numbers a, b, c representing a k-query. You should do the following:
    • i = a xor last_ans
    • j = b xor last_ans
    • k = c xor last_ans
    After that 1 ≤ i ≤ j ≤ n, 1 ≤ k ≤ 109 holds.
    Where last_ans = the answer to the last query (for the first query it's 0).

Output

For each k-query (i, j, k), print the number of elements greater than k in the subsequence ai, ai+1, ..., aj in a single line.

Example

Input:
6
8 9 3 5 1 9
5
2 3 5
3 3 7
0 0 11
0 0 2
3 7 4

Output:
1
1
0
0
2

[Edited by EB]

There are invalid queries. Assume the following:
  • if i < 1: i = 1
  • if j > n: j = n
  • if i > j: ans = 0

Added by:amirmd76
Date:2015-04-17
Time limit:0.200s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All

hide comments
2015-04-19 17:48:25 Satyaki Upadhyay
After the execution of the third query, the answer is 0. So, for the fourth query, the actual range is [0^0, 0^0] which is [0, 0] but doesn't lie in the range [1, n]. Is this a mistake or is the test case fine?

Edit: The test case is incorrect. I got AC assuming its wrong.


Last edit: 2015-04-19 18:01:17
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