INVCNT - Inversion Count

Let A[0...n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n <= 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] <= 10^7). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6

hide comments
2013-07-10 05:01:21 Geanyous
lol printing "%d" instead of "%lld" cost me an WA..
2013-06-25 16:49:53 Erti-Chris Eelmaa
0.49 :-))
2013-06-19 19:48:22 Vipul Pandey
got AC in the first attempt! just use merge sort with a bit modification. But a good one to learn a new thing.
2013-06-12 09:38:08 virtuazx
Be careful about the typecasting and longlong stuff....It kills a lot of your time!!
2013-04-20 18:51:16 ওয়াসী (Wasi)
AC at first try...


Last edit: 2013-08-21 15:01:40
2013-04-15 16:21:46 Tony Stark
I have to agree with mister Kent.

Last edit: 2013-04-03 13:03:25
2013-04-15 16:21:46 luccasiau
Binary Indexed Trees are much more cooler than merge sort :)
2013-04-15 16:21:46 ankitsablok89
Easy one with Merge Sort :)
2013-04-15 16:21:46 suyog patil
easy 1 with merge sort!!! try ur college assignment program..:P
2013-04-15 16:21:46 Akash Goel
changing the no of inversions to long long didnt help, still stuck at TLE. :(
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