Submit | All submissions | Best solutions | Back to list |
IITKWPCB - Check the coprimeness |
Find largest non-negative number less than or equal to floor (N/2) which is coprime to N.
Two number a and b are considered to coprime if gcd(a, b) = 1.
Input
T : number of test cases (T ≤ 1000).
For next T lines, every line contains n (1 ≤ n ≤ 1012).
Output
For each test case, output the answer as described in the problem statement.
Example
Input: 4
3
4
5
100
Output: 1
1
2
49
Added by: | praveen123 |
Date: | 2013-08-05 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | IITK ACA CSE online judge |
hide comments
|
|||||||
2023-05-02 21:18:06
think brutforce better |
|||||||
2021-02-26 12:23:06
<snip> Please correct if i'am wrong [NG]: It's wrong to spoil. Last edit: 2021-02-26 16:15:15 |
|||||||
2019-02-01 04:59:02
Don't worry about n==1 case. |
|||||||
2018-12-25 15:30:24
ac in one go |
|||||||
2018-06-30 17:20:57
Just make sure that if you are using C you might keep getting a wrong answer even though your logic might be correct because of the incorrect data type. Use unsigned long long int and also while using printf, try using inttype.h library! otherwise,core logic is simple. |
|||||||
2018-03-01 20:56:21
Easy Question. At first I just ran a loop to find the GCD=1 condition it passed (had guessed that we'll always have an answer) but then the comments provided with another approach the pattern approach which was too easy to code :) |
|||||||
2018-01-04 14:51:29
brute force it and get the pattern and then its O(1) |
|||||||
2017-11-07 09:38:57
no need of gcd,floor,just should hv an idea of coprime no. i.e. they have only d factor 1 in common |
|||||||
2017-06-28 15:13:24
develop the pattern and thats it |
|||||||
2017-06-26 20:12:45
waste my time where O(1) solution exists. Problem statement should be changed to "See the test cases and develop solution" |