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HFUN - H Function |
The issue of this problem is to find out the value for H(N), where H(N) is the sum of all digits of N, but if H(N) > 9 then H(N) = H(H(N)). Rather it is want that you find H(N!).
1 <= T <= 300000
0 <= N <= 1000000
Input
T
N1
N2
...
NT
Output
H(N1!)
H(N2!)
...
H(NT!)
Example
Input:
2
1
5
Output:
1
3
| Added by: | leandro |
| Date: | 2010-02-23 |
| Time limit: | 1s |
| Source limit: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Languages: | All except: ADA95 ASM64 BASH BF C99 CLPS LISP sbcl LISP clisp D ERL HASK ICK LUA NEM NICE OBJC OCAML PIKE PRLG-swi SCALA SCM guile SCM qobi ST SQLITE TCL WHITESPACE |
| Resource: | Own Problem |
hide comments
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2012-09-03 18:17:29 numerix
@Mitch: Explanation e.g. here: www.spoj.pl/forum/viewtopic.php?f=20&t=5918 |
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2012-09-02 21:18:57 Mitch Schwartz
There's something strange with the input formatting. In Python, int() gives AC, but eval() gives NZEC. @numerix: Thank you for explaining. Last edit: 2012-09-04 00:30:03 |
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2011-06-19 03:28:09 isak
N can be 10^6 and we have to calculate h(N!) !!! |
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2010-09-11 11:36:05 Piotr KÄ…kol
Why not increase time limit to 5sec? For Ruby 3sec are not enought. |
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