HAP01 - Play with Binary Numbers

Let S be the binary representation of an integer. We define two functions a(i) and b(i) such that:

  • a(i) = Number of occurrences of '1' at odd positions of S,
  • b(i) = Number of occurrences of '1' at even positions of S.

For example: for integer 19, S = 10011, so a(19) = 2 and b(19) = 1.

Input

First line contains an integer T, the number of test cases. Then T lines follow. On each line, you will be given three integers M, N, K.

Output

For each test case output a single integer R, where R is the number of integers 'i' between M and N (both inclusive) such that absolute difference of a(i) and b(i) is equal to K. The answer to each each test case should be on a separate line.

Constraints

T ≤ 50
1 ≤ M < N ≤ 1019
1 ≤ N - M ≤ 106
0 ≤ K ≤ 50

Example

Input:
1
1 10 2

Output:
2

Added by::-)
Date:2013-04-16
Time limit:1.201s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All
Resource:own

hide comments
2016-12-27 19:28:38 prakash
very easy
2016-07-05 19:22:13
didn't understand.....same code AC in C but TLE in C++
2016-07-03 21:20:43
such a beautiful implementation of bitwise operator...worth solving
2016-02-27 04:27:15
Wooo.....
AC in one go!!!
2015-08-29 18:55:33 shantanu tripathi
@ admin 15011977 plzz check this id why its giving TLE....and when i changed variable from int to long long it got AC..
2015-06-18 15:57:03 chin
Brute force works!!!..:D
2014-09-14 13:07:19 vank
So here comes the Century :)
2014-08-21 21:49:36 Barack Obama
submission id 12204868, it shows wrong answer.....but test cases running well....what are the possible problems...??
2014-06-18 10:40:57 vb30
AC...
100th classical!!!

2014-02-13 09:30:09 Bhavik
brute force works....AC in first attempt
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.