GSS3 - Can you answer these queries III

You are given a sequence A of N (N <= 50000) integers between -10000 and 10000. On this sequence you have to apply M (M <= 50000) operations:
modify the i-th element in the sequence or for given x y print max{Ai + Ai+1 + .. + Aj | x<=i<=j<=y }.

Input

The first line of input contains an integer N. The following line contains N integers, representing the sequence A1..AN.
The third line contains an integer M. The next M lines contain the operations in following form:
0 x y: modify Ax into y (|y|<=10000).
1 x y: print max{Ai + Ai+1 + .. + Aj | x<=i<=j<=y }.

Output

For each query, print an integer as the problem required.

Example

Input:
4
1 2 3 4
4
1 1 3
0 3 -3
1 2 4
1 3 3

Output:
6
4
-3

Added by:Bin Jin
Date:2007-08-03
Time limit:1s
Source limit:5000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: CPP
Resource:own problem

hide comments
2015-01-05 21:13:44 rishabh aggarwal
tle...
any solution?????
2014-12-19 07:14:04 j1k7_7(JaskamalKainth)
Just one change from GSS1. :)
2014-12-03 13:35:35 Rahul
Great problem for learning segment trees. :)
2014-11-12 15:44:33 mayank
This test case might help.
10
-1 4 5 6 -3 -4 -5 -6 -7 -8
1
1 1 10
2014-09-03 18:06:56 Mostafa 36a2
@EB :I think there should be a statement says: "1<=x<=N" and y in the second query is "1<=y<=N" .
2014-08-29 19:36:43 Mostafa 36a2
@The Bear : You have to find any sub-range that is the maximum
"print max{Ai + Ai+1 + .. + Aj | x<=i<=j<=y }"
so if i=4,j=4 A[4]=4 is the maximum

Last edit: 2014-09-03 17:59:49
2014-08-07 21:00:50 Ahmedali Durga
What is Wrong answer#0?
2014-07-30 09:27:02 vikrant
@Bin Jin what does #0 mean?
2014-07-20 15:24:20 Anirudh Rayabharam
This is complete nonsense. Why is the source limit so low? The standard is 50000 Bytes.
2014-05-22 05:40:50 Mike OBeirne
For Java, I had to use a faster scanner (using BufferedInputReader), as well as using StringBuilder for the output. Was able to finally get it to pass, though!
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.