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GOT - Gao on a tree |
There's a tree, with each vertex assigned a number. For each query (a, b, c), you are asked whether there is a vertex on the path from a to b, which is assigned number c?
Input
There are multiple cases, end by EOF.
For each case, the first line contains n (n <= 100000) and m (m <= 200000), representing the number of vertexes (numbered from 1 to n) and the number of queries.
Then n integers follows, representing the number assigned to the i-th vertex.
Then n-1 lines, each of which contains a edge of the tree.
Then m lines, each of which contains three integers a, b and c (0 <= c <= n), representing a query.
Output
You should output "Find
" or "NotFind
" for every query on one line.
Output a blank line AFTER every case.
Example
Input: 5 5 1 2 3 4 5 1 2 1 3 3 4 3 5 2 3 4 2 4 3 2 4 5 4 5 1 4 5 3 Output: NotFind Find NotFind NotFind Find
Added by: | lxyxynt |
Date: | 2012-08-17 |
Time limit: | 0.602s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
hide comments
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2024-08-30 06:37:17
AC on 7th submission using your mom ezzz Last edit: 2024-08-30 06:40:31 |
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2021-05-20 14:31:40
Be careful to: There are multiple cases, end by EOF. (0 <= c <= n) |
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2021-03-11 15:15:56
learn path queries on trees (Euler tour technique) |
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2020-06-02 22:47:07
Why 0.602 seconds? Why not just leave it at 1 second? Last edit: 2020-06-02 23:03:15 |
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2020-05-11 19:13:51
i got wa for not considering c=0 and cin cout can cause tle . easily solvable using HLD. :D |
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2020-01-29 16:00:40
good Last edit: 2020-01-29 16:00:53 |
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2019-08-28 10:53:05
AC in one go |
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2019-08-25 09:02:54
solved with HLD and offline queries, O(m*log^2n) Last edit: 2019-08-25 11:34:03 |
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2018-02-10 06:05:06
ez solve in one submission |
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2017-08-16 19:24:57
C++14 Clang 4.0 is OK with DFS-recursion. No SIGSEGV. |