FINDSR - Find String Roots

In mathematics, the N-th root of a number M, is a number K such that KN = M , i.e. KKK ... K = M where K is multiplied N times.

We can translate this into strings. In string notation, the juxtaposition is concatenation instead of multiplication. So, the N-th root of a string S is another string T such that TN = S, where T N = TTT ... T is the string T concatenated N times. For instance, if S = “abcabcabcabc”, for N = 2 the string T = “abcabc” is the N-th root of S, while for N = 4 its N-th root is T = “abc”. Note that for N = 1 any string S is the N-th root of S itself.

Given a string S you have to find the maximum N such that the N-th root of S exists. In the above example the answer would be 4, because there is no N-th root of S = “abcabcabcabc” for N > 4.

Input

The input contains several test cases, each one described in a single line. The line contains a non-empty string S of at most 105 characters, entirely formed of digits and lowercase letters. The last line of the input contains a single asterisk (“*”) and should not be processed as a test case.

Output

For each test case output a single line with the greatest integer N such that there exists a string T that concatenated N times is equal to S.

Example

Input:
abcabcabcabc
abcdefgh012
aaaaaaaaaa
*

Output:
4
1
10

Added by:Pablo Ariel Heiber
Date:2010-08-22
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS OBJC PERL6 VB.NET
Resource:FCEyN UBA ICPC Selection 2009

hide comments
2010-09-01 00:28:05 Vaibhav
I actually do it without any major string algorithms. But a little slower than other ACs
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