FACEFRND - Friends of Friends

Bob uses a social networking site almost all the time. He was wondering what are Friends of Friends in that social networking site? If “X” is his friend, and “Y” is X’s friend but “Y” is not his friend, then “Y” is called his friend of friend. You have to find how many friends of friends Bob has. (Each user in that social networking site has a unique 4-digit ID number)

Input

First line contains a integer “N” (1 ≤ N ≤ 100) the number of friends in Bob's Profile. Then follow N lines.

First Integer in each line is the ID number of Bob's friend, then an integer “M” (1 ≤ M ≤ 100) is the number of people in his friend list. Then follow M integers in that line, denoting the ID number of friends in his friend list (excluding Bob). 

Output

Output a single integer denoting Bob's number of friends of friends.

Example

Input:
3
2334 5 1256 4323 7687 3244 5678
1256 2 2334 7687
4323 5 2334 5678 6547 9766 9543

Output:
6

Added by:Ankit Kumar Vats
Date:2011-10-20
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All
Resource:Own Problem

hide comments
2016-01-29 17:25:22
AC in first go... Easy , no need for 2-d arrays , sorting etc.
2016-01-29 14:48:46
Had a Compile time Error because I submitted C++ code into C Compiler
Very Stupid
AC in 2nd go...;)
Simple with Sets.
2016-01-24 08:32:34
pure hashing concept ! single shot AC B)
No sorting, No STL, No Collections, No comparisons of array values and no extra shit !
2016-01-15 12:18:45
Set 'FriendsOfFriends' - Set 'Friends' = AC
2016-01-06 14:20:05 Shantanu Banerjee
All ID's are not of 4 digits. Got 2 WA's
2016-01-03 18:46:00
one array one try ac pretty simple :)
2015-12-27 09:30:00
AC Easy with STL Set
2015-12-26 01:32:09
No need of STL, sets, sorting e.t.c..Just used a simple array. Sorting that array was not needed. Keep it simple. :)
2015-12-21 18:58:12 Junaid
Extremely easy problem....use Sets in JAVA...no need of sorting or anything..AC in one go...;)
2015-11-29 16:58:51
used maps
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