EIGHTS - Triple Fat Ladies

Pattern Matchers have been designed for various sorts of patterns. Mr. HKP likes to observe patterns in numbers. After completing his extensive research on the squares of numbers, he has moved on to cubes. Now he wants to know all numbers whose cube ends in 888.

Given a number k, help Mr. HKP find the kth number (indexed from 1) whose cube ends in 888.

Input

The first line of the input contains an integer t, the number of test cases. t test cases follow.

Each test case consists of a single line containing a single integer k (1 <= k <= 2000000000000).

Output

For each test case, output a single integer which denotes the kth number whose cube ends in 888. The result will be less than 263.

Example

Input:
1
1

Output:
192

Added by:Matthew Reeder
Date:2006-10-30
Time limit:1.197s
Source limit:30000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ERL JS-RHINO NODEJS PERL6 VB.NET
Resource:Al-Khawarizm 2006

hide comments
2018-06-27 08:55:31
getting wrong answer using simple maths
2018-06-09 19:30:53
The test case may be long.

Last edit: 2018-06-09 19:31:32
2018-06-04 14:21:39
first run a bruteforce program to print you the first few elements of the sequence (using string manipulation). notice pattern, get ac in 7 lines (or less)
2018-05-31 11:21:42
test
2018-04-06 20:57:47
can anyone tell me how to figure out that the numbers will be in AP?.
if you can please e-mail me at sanjib.sah@yahoo.com
Thank You :)
2018-03-11 11:21:18
@sreejoy4242
good observation!!
if k==1
192
else
192+(k-1)*250

Last edit: 2018-03-11 11:21:53
2018-03-09 15:07:54
There should be another test case.
Thanks for suggesting arithmetic progression.
2018-03-06 11:57:34
Total time waste
2018-03-03 08:26:06
AC in one go.. :)
2018-02-19 05:13:28
if k == 1 then 192
else 192 + (k-1)*250
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