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EELCS - Easy Longest Common Subsequence |
A common subsequence between two strings A and B is defined as 2 sets { i0 , i1 , i2 , i3 , ... , ik } { j0 , j1 , j2 , j3 , ... , jk } such that 0 <= i0 < i1 < i2 < i3 < ... < A.length() and 0 <= j0 < j1 < j2 < j3 < ... < B.length() and A[ i0 ] = B[ j0 ], A[ i1 ] = B[ j1 ] , ... , A[ ik ] = B[ jk ]. Given two strings A and B print the length of the longest common subsequence between them.
i.e. "a", "d","cd" are common subsequence between the two strings "abcd" and "adcd" while "acd" is the longest common subsequence between them.
Input
First line contains a string A (1 <= A.lenth() <= 7).
Second line contains a string B (1 <= B.length() <= 7).
Each string is composed of lower case letters only ('a' -'z').
Output
Prints one line containing the length of the longest common subsequence.
Example
Input:
abcd
adcd Output: 3
Added by: | Omar ElAzazy |
Date: | 2012-03-17 |
Time limit: | 2s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
hide comments
2020-10-26 14:41:08
Easy recursive soln:) |
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2020-04-14 07:02:25
AC in one go..... ;-) |
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2019-06-10 17:48:49
AC in one go:) |
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2018-06-05 09:24:57
AC in one go |
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2018-03-24 21:20:13
Just a simple dp approach . AC in 1 Go . |
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2016-10-16 15:57:28
there is only one test case |
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2015-05-23 21:30:59
<p>nice</p> |
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2014-10-06 13:36:37 Devashish
till when do we take the input. EDIT: Got it ..thanks a lot for this problem :) ANS: while(scanf("%s",&s1)!=EOF && scanf("%s",&s2)!=EOF) in c++ for those who are not getting it. Last edit: 2014-10-06 13:45:03 |