EDIST - Edit distance

You are given two strings, A and B. Answer, what is the smallest number of operations you need to
transform A to B?

Operations are:

  1. Delete one letter from one of strings
  2. Insert one letter into one of strings
  3. Replace one of letters from one of strings with another letter

Input

T - number of test cases

For each test case:

  • String A
  • String B

Both strings will contain only uppercase characters and they won't be longer than 2000 characters. 

There will be 10 test cases in data set.

Output

For each test case, one line, minimum number of operations.

Example

Input:
1
FOOD
MONEY

Output:
4

Added by:Mislav Balunović
Date:2010-02-28
Time limit:15s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS OBJC PERL6 SQLITE VB.NET
Resource:Internet

hide comments
2017-12-19 11:13:00
Note :
1. Do it yourself.
2.Can refer web/youtube.
3.Again code yourself implementing the logic
4.Dont forget to clear the buffer using cin.ignore() :p costed me 2WA
2017-09-16 19:12:14
I tried to solve it by finding LCS....the
cout << max(s.length(),s1.length()) - LCS << endl;
still got WA
2017-08-29 10:34:47
Levenshtein distance ... :)
2017-08-29 05:02:13
stop reading comments
2017-06-22 17:55:15
same code accepted in c++ , WA in Java.
2017-05-27 13:16:55 arvind002
Great problem!! Declare a global array , it will save you a wrong answer :)
2017-05-22 17:53:23
Learnt something new :D
2017-05-20 16:25:46
For Python, use PyPy 2.6.0
2017-05-18 17:08:23
Please make sure that ur array for both a and b should be of size 2001 , in case of 2000 it will show wrong answer .
Costed me 2 WA ...
2017-05-16 05:04:19
After lot's of effort, finally AC !!
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.