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EASYMATH - EASY MATH |
You will be given 4 numbers: n m a d.
find count of numbers between n and m (inclusive) not divisible by (a) or (a+d) or (a+2d) or (a+3d) or (a+4d).
Input
first line has number t - number of test cases.
each test case has 4 numbers n m a d.
Output
Single line having single number giving the count.
Constraints
1 <= n <= m <= 2^32
1 <= a <= 2^32
1 <= d <= 2^32
2 <= t <= 100
Example
Input: 3 1 10 2 2 20 100 3 3 100 1000 4 5 Output: 5 54 543
Also try the challenge version at www.spoj.com/problems/EASYMATC/
Added by: | Devil D |
Date: | 2012-04-17 |
Time limit: | 0.100s-1s |
Source limit: | 20000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own |
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2018-10-16 19:58:30
very nice problem :) |
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2018-09-10 19:09:01
solvable using inclusion-exclusion principle take care of implementation |
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2017-09-01 00:29:27
tle by iteration.. |
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2016-02-01 12:05:01 kejriwal
easy math :) |
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2015-10-29 06:02:54
got TLE :-) |
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2015-10-27 13:07:51 Sonu Sharma
Take special care of :n & m (inclusive) <<<<<not>>>>> divisible by |
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2015-09-27 20:03:42 arpita
anyone had its correct ans? plz comment ur id, |
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2015-09-27 09:37:23 varun yadav
my solution is showing WA,, what should i do ??? link ----> http://ideone.com/yAVncM |
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2015-01-07 17:52:44 Abhinav
getting WA at 9th case any tricky case ? |
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2014-11-18 13:39:31 ayushi agarwal
why unsigned int doesn't work and long long int work in c++ |