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DIVSUM - Divisor Summation |
Given a natural number n (1 <= n <= 500000), please output the summation of all its proper divisors.
Definition: A proper divisor of a natural number is the divisor that is strictly less than the number.
e.g. number 20 has 5 proper divisors: 1, 2, 4, 5, 10, and the divisor summation is: 1 + 2 + 4 + 5 + 10 = 22.
Input
An integer stating the number of test cases (equal to about 200000), and that many lines follow, each containing one integer between 1 and 500000 inclusive.
Output
One integer each line: the divisor summation of the integer given respectively.
Example
Sample Input: 3 2 10 20 Sample Output: 1 8 22
Warning: large Input/Output data, be careful with certain languages
Added by: | Neal Zane |
Date: | 2004-06-10 |
Time limit: | 3s |
Source limit: | 5000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | Neal Zane |
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2016-10-20 06:39:54
i'm getting TLE why?? :( |
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2016-10-19 00:34:34
i am getting an internal error , any help ? and my internet connection is not bad |
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2016-10-16 17:01:52
hey some one is trying now? i am having troubles with execution time ... |
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2016-09-30 12:40:10 Dimas Hirda Pratama
TLE :( |
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2016-09-24 17:11:03 ajay
what is the basic idea to attempt to this problem |
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2016-09-14 17:24:39
why am I getting WA although the code gives the right output on my machine? Please anybody help. I'm stuck. |
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2016-09-14 15:33:33 Gaurav
Any idea what's wrong with solution # 17711087. I am gettign WA. It's in golang Missed out case where num=1. Last edit: 2016-09-14 15:36:31 |
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2016-08-13 08:51:31
I don't know why I'm getting WA when I believe my logic is correct and sample cases are also getting passed. Please see my solution at: <snip> Last edit: 2023-05-09 11:42:07 |
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2016-06-19 05:45:07
don't think to much.....simple |
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2016-06-17 19:52:14
easy problem, AC in first go... |