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DILEMMA - DILEMMA |
As a part of his maths test, little Max aged five has to find out maximum of two concatenated numbers written on a card. Unfortunately the card was torn by his elder brother into two pieces. Max has to now join the two pieces. If one piece has 78 and the other has 783, he can join them in two ways to get 78783 or 78378. He has to find the maximum number. Can you write a program to help him out?
Input
The first line must have the two numbers. Each of the numbers can have n-digits, 1 <= n <= 30,000. The numbers are separated by a space.
Output
The maximum number of the two formed after concatenation must be printed.
Example
Input: 78 783 Output: 78783
Input: 567 78 Output: 78567
Added by: | Vasavi OPC Team |
Date: | 2013-01-21 |
Time limit: | 1s-5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | ASM32-GCC MAWK BC C-CLANG C NCSHARP C++ 4.3.2 CPP CPP14 CPP14-CLANG COBOL COFFEE D-CLANG D-DMD DART ELIXIR FANTOM FORTH GOSU GRV JAVA JS-MONKEY JULIA KTLN NIM OBJC OBJC-CLANG OCT PICO PROLOG PYTHON PYPY PYPY3 R RACKET RUST CHICKEN SQLITE SWIFT UNLAMBDA VB.NET |
hide comments
2019-08-04 14:19:53
hint : use string and compare ac in one go |
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2018-06-08 03:57:40
42B here. |
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2013-01-24 12:44:41 (Tjandra Satria Gunawan)(曾毅昆)
mine 64B, too easy for python because python has build in function to solve this... EDIT: finally got it, now 52B too ;-) thanks, I learned something new about python.. Last edit: 2013-01-22 21:27:16 |
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2013-01-24 12:44:41 Francky
53B of trivial code, to be hidden imho... EDIT : 52 without the trailing \n, @tjandra, you should have make a double useless cast ;-) Last edit: 2013-01-22 21:02:05 |
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2013-01-24 12:44:41 Alex Anderson
Test cases are fine, but this problem is too easy. I'd recommend hiding it. Or making it better, like, you have K numbers, need to concatenate in any order, find max possible. Which is slightly better. |
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2013-01-24 12:44:41 nani
Last edit: 2014-02-08 03:29:43 |
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2013-01-24 12:44:41 Santiago Palacio
Jmm i believe test cases might be wrong... |