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CUBEFR - Cube Free Numbers |
A cube free number is a number who’s none of the divisor is a cube number (A cube number is a cube of a integer like 8 (2 * 2 * 2) , 27 (3 * 3 * 3) ). So cube free numbers are 1, 2, 3, 4, 5, 6, 7, 9, 10, 11, 12, 13, 14, 15, 17, 18 etc (we will consider 1 as cube free). 8, 16, 24, 27, 32 etc are not cube free number. So the position of 1 among the cube free numbers is 1, position of 2 is 2, 3 is 3 and position of 10 is 9. Given a positive number you have to say if its a cube free number and if yes then tell its position among cube free numbers.
Input
First line of the test case will be the number of test case T (1 <= T <= 100000) . Then T lines follows. On each line you will find a integer number n (1 <= n <= 1000000).
Output
For each input line, print a line containing “Case I: ”, where I is the test case number. Then if it is not a cube free number then print “Not Cube Free”. Otherwise print its position among the cube free numbers.
Example
Sample Input: 10 1 2 3 4 5 6 7 8 9 10 Sample Output: Case 1: 1 Case 2: 2 Case 3: 3 Case 4: 4 Case 5: 5 Case 6: 6 Case 7: 7 Case 8: Not Cube Free Case 9: 8 Case 10: 9
Added by: | Muhammad Ridowan |
Date: | 2011-06-14 |
Time limit: | 0.100s-1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own. For alternate thanks Sayef Azad Sakin |
hide comments
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2011-06-16 11:08:41 Lukmanul Hakim
Are you sure that time limit for some test case are 0s? :| |
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2011-06-16 10:48:23 Suprabh Shukla
Maybe the problem could be made more interesting by increasing the limit on n and decreasing the no. of tests a little so that pre-computation is made impossible ... |
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2011-06-15 15:28:10 AJAY
am getting time limit exceeded :( pls help!! |
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2011-06-14 17:24:29 Filip Ice
more test cases please, getting wrong answer.. |