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CPTTRN5 - Character Patterns (Act 5) |
Using two characters: . (dot) and * (asterisk) print a grid-like pattern. The grid will have l lines, c columns, and each square shaped element of the grid will have the height and width equal to s.
Moreover, each of the grid elements will have a diagonal. The diagonal of the first square in the first line of the grid is directed towards down and right corner - use the \ (backslash) character to print it; while the next diagonal will be directed towards upper right corner - use the / (slash) character to print it. Print the successive diagonals alternately (please consult the example below).
Input
You are given t - the number of test cases and for each of the test case three positive integers: l - the number of lines, c - the number of columns in the grid and s - the size of the single square shaped element.
Output
For each of the test cases output the requested pattern (please have a look at the example). Use one line break in between successive patterns.
Example
Input: 3 3 1 2 4 4 1 2 5 2 Output: **** *\.* *.\* **** *./* */.* **** *\.* *.\* **** ********* *\*/*\*/* ********* */*\*/*\* ********* *\*/*\*/* ********* */*\*/*\* ********* **************** *\.*./*\.*./*\.* *.\*/.*.\*/.*.\* **************** *./*\.*./*\.*./* */.*.\*/.*.\*/.* ****************
Added by: | kuszi |
Date: | 2012-09-04 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
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2015-12-23 12:23:48
You can reuse the pattern of *s of CPTTRN4, and with just 2 loops over i and j, distinguish the cases for / and \ depending on modulos of i+j or i-j Last edit: 2015-12-23 12:26:47 |
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2015-11-22 23:41:44 Micha³ Krokocki
Ok, I was trying to pass it for a few days, finally I made it! Tips? First try to make it work for two sizes of square - for 1 and for 2. If you make it, changing it to flexible version is easy. |
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2015-11-19 14:08:33
I just passed it, give you some tips. i for row, j for column for bigger block; k for row, l for column of smaller block. 1. judge (i+j)&1 for '/' or '\'. 2. loop level i > k > j > l |
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2015-11-19 10:30:53 abhinaw tiwari
CPTTRN1, CPTTRN2, CPTTRN3, CPTTRN4 were easy. But I am finding CPTTRN5 a bit difficult. Can anyone help me out please? |