COMDIV - Number of common divisors

You will be given T (T<=10^6) pair of numbers. All you have to tell is the number of common divisors between two numbers in each pair.

Input

First line of input: T (Number of test cases)
In next T lines, each have one pair A B (0 < A, B <= 10^6)

Output

One integer describing number of common divisors between two numbers.

Example

Input:
3
100000 100000
12 24
747794 238336 Output: 36
6
2

Added by:Mir Wasi Ahmed
Date:2010-10-31
Time limit:0.600s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:Own problem, used in UODA TST

hide comments
2012-02-04 12:23:47 krishnan
Atlast I got AC

Last edit: 2012-02-04 12:25:03
2012-01-19 08:37:00 Harpreet Singh Khurana
can somebody give some more test cases with boundary cases included......is (0,0) also included

Last edit: 2012-01-19 08:37:52
2011-11-28 20:17:32 Albert Chen
************Warning***********
Very IO related!!!
I used very naive algorithm and got TLE using cin/cout, but accepted with scanf/printf!!!!!!
2011-11-09 22:48:15 Hazem
i use
O(n/2 + lnln(n)) in c++
and tle!!!!!!!!!!!!!!!!!!!!!!!
2011-11-08 07:22:52 ??????????????
when checking upto (min(a,b))/2 TLE is coming.plz.somebody help me
2011-10-31 16:43:33 ontole
sqrt(min(a,b)) is giving tle!!!
2011-10-06 16:49:29 Yasser Kamel
i spend a day for this :
cin and cout did not work
2011-10-05 19:47:39 sri
O(sqrt(min(x,y)) is getting TLE???
somebody guide me
2011-07-13 14:11:10 Dante is not a Geek
Can you give a test case where my code fails? I do not understand why there can be overflow for such small numbers. Submission ID: 5374241

Last edit: 2011-07-14 01:10:56
2011-06-27 16:46:07 Psycho
@radhakrishnan u r comparing it wit finding prime which can be done in (sqrt(n)) but here, I think its solution requires at least O(min(x,y)) time correct me if i am wrong
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