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CLOPPAIR - Closest Point Pair |
You are given N points on a plane and your task is to find a pair of points with the smallest Euclidean distance between them.
All points will be unique and there is only one pair with the smallest distance.
Input
First line of input will contain N (2<=N<=50000) and then N lines follow each line contains two integers giving the X and Y coordinate of the point. Absolute value of X,Y will be at most 10^6.
Output
Output 3 numbers a b c, where a, b (a<b) are the indexes (0 based) of the point pair in the input and c is the distance between them. Round c to 6 decimal digits.
See samples for more clarification.
Input:
5
0 0
0 1
100 45
2 3
9 9
Output:
0 1 1.000000
Input:
5
0 0
-4 1
-7 -2
4 5
1 1
Output:
0 4 1.414214
Added by: | SALVO |
Date: | 2011-04-14 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Standard Problem |
hide comments
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2020-08-18 17:37:05
Can be done using line sweep algorithm in nlogn |
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2020-06-13 11:02:06
I have submitted more than 15 times but still stuck at line 179 in my code <snip> Please someone help Last edit: 2022-07-26 21:52:08 |
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2020-04-03 21:30:21 Saksham
'rounding to 6 digits' - this got me. |
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2020-01-16 05:09:30 Eddy Cael
You can use long long or double, it no makes a real difference. |
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2020-01-16 05:04:33 Eddy Cael
Don't waste time in precision issues... Make sure that the algorithm is right and a<b. That's all. |
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2019-11-10 19:35:02
time waste |
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2019-07-05 11:22:00
acos |
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2019-07-05 11:20:41
atan2(y,x) |
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2019-05-11 14:48:33
Getting TLE with n*logn algo in JAVA...Anyone got AC in JAVA ?? |
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2019-02-10 14:04:48
badihijat |