CANTON - Count on Cantor

One of the famous proofs of modern mathematics is Georg Cantor's demonstration that the set of rational numbers is enumerable. The proof works by using an explicit enumeration of rational numbers as shown in the diagram below.

1/1 1/2 1/3 1/4 1/5 ...
2/1 2/2 2/3 2/4
3/1 3/2 3/3
4/1 4/2
5/1

In the above diagram, the first term is 1/1, the second term is 1/2, the third term is 2/1, the fourth term is 3/1, the fifth term is 2/2, and so on.

Input

The input starts with a line containing a single integer t <= 20, the number of test cases. t test cases follow.

Then, it contains a single number per line.

Output

You are to write a program that will read a list of numbers in the range from 1 to 10^7 and will print for each number the corresponding term in Cantor's enumeration as given below.

Example

Input:
3
3
14
7

Output:
TERM 3 IS 2/1
TERM 14 IS 2/4
TERM 7 IS 1/4

Added by:Thanh-Vy Hua
Date:2005-02-27
Time limit:5s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS PERL6 VB.NET
Resource: ACM South Eastern European Region 2004

hide comments
2014-08-20 19:25:13 Abhishek Singh
help needed!
it is showing compilation error, but the code is compiled and running correctly on my computer! i m using C++ on Visual Studio 2013.
2014-08-17 07:45:14 opcode
not able to completely understand the pattern, taken help from web :(
2014-08-10 22:29:35 shreya sahu
green in first attempt! :)
2014-07-18 10:04:36 sasuke
Got AC in the first attempt

Last edit: 2014-07-18 10:04:50
2014-06-27 16:06:23 Shireen Nagdive
AC in one go :D :D
2014-06-24 08:48:29 Steven Hans Limantoro
Just use Diagonal Argument :)

Last edit: 2014-06-24 08:48:46
2014-06-08 11:06:39 uchiha
0.00 in first try
2014-06-03 22:09:53 insane0808
0.00 AC ...USE INDEXING !!!
2014-05-21 15:27:51 newbie
i got term 10000000 as 2844/1629 and all random numbers i calculated manually and got the right result.then why am i getting WA? pls help
2014-04-19 22:48:08 Satinjal Yadav
Green light in 1st attempt...
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