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CAM5 - prayatna PR |
help the Prayatna pr team
Well, the annual technical symposium of Department of Computer Technology is around the corner. All that we need, to make it a grand success is Publicity among the peer groups ( ofCourse the sponsors too :P ). We decided to share the job between the student groups. As per the plan we decided to meet people in person and influence them to attend Prayatna. But to meet them we have to go to various student groups. To do so, we had to cut our classes. But being studious. students refused to cut more classes. Instead of meeting every one in person we decided to meet few people such that the person to whom we pass the news will spread it to all his friends. And those friends will pass it to other friends and so on. Your task is to find the number of people to be met by the organizers to spread the news.
Caution: Large I/O
Input
First line of input is 't' - Test cases. Follwed by N, the number of peers in the testcase ( 0 to N-1 ). followed by the number of friend description 'e'. Following are 'e' descriptions of type "a b" denoting 'a' friends with 'b'. If 'a' is friends with 'b' then 'b' is friends with 'a'.
Output
Output contains t line, the number of people, the organizers have to meet in person for each test case.
Example
Input: 2 4 2 0 1 1 2 3 0 Output: 2 3
Explanation
case 1 : 0 is friends with 1; 1 is friends with 2; so if we pass the news to 0 & 3, news will pass it to the entire N peers.
case 2 : no one is friends with any one. So we have to meet every one in person.
Constraints
t = 10
2 <= N <= 100000
0 <= e <= N/2
Added by: | karthikeyan |
Date: | 2012-01-11 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | own problem |
hide comments
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2018-01-14 14:01:16
simple question of dfs : consider connected graphs ac in one go |
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2017-12-25 11:47:14 Divyam Shah
Same Logic TLE in Java AC in C++ |
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2017-10-21 23:56:44
Ac in one go! in 1 minute :P |
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2017-10-02 07:08:51
silly mistake costed me a WA finally AC!! |
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2017-08-22 20:15:22
AC in one Go...0.14 sec......DFS is enough.! |
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2017-07-22 10:55:24
used Disjoint set (0.03 secs) |
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2017-07-13 12:19:55
AC IN 1GO My 100th :) Simple dfs |
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2017-06-30 20:50:13
Clear the vector in each TC, otherwise WA. Nice problem.Can be done with Disjoint union and DFS. |
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2017-06-21 22:31:21
My first Graph Question Took me around 1.5 hours/ But finally, AC in one go :) |
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2017-06-13 13:41:17
just count the connecting components and you are good to go!!! |