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You are given a sorted array of numbers, and followed by number of queries, for each query if the queried number is present in the array print its position, else print -1.
Input
First line contains N Q, number of elements in the array and number of queries to follow.
Second line contains N numbers, the elements of the array. Each number will be -10^9 <= ai <= 10^9, 0 < N <= 10^5, 0 < Q <= 5*10^5
Output
For each element in the query, print the elements 0 based location of its first occurence, if present, otherwise print -1.
Example
Input: 5 4 2 4 7 7 9 7 10 4 2 Output: 2 -1 1 0
Added by: | jack(chakradarraju) |
Date: | 2012-03-13 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | NITT Class |
hide comments
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2017-09-06 17:59:01
Remember: it's a SORTED vector as input. I've ignored that and got TLE. Last edit: 2017-09-06 18:00:39 |
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2017-08-27 22:27:46
python is giving TLE :( how can i remove it.. |
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2017-08-25 23:17:41
can use map..AC in 0.29 seconds |
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2017-07-30 21:12:27
I tried python but got TLE in C++ I got AC with printf and scanf |
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2017-05-16 09:34:10
It's Seems easy at first,Unless TLE starts popping out on your screen. Some Tips: Dont use lower_bound,it will give TLE. Don't use Fast I/O Technique,Use printf scanf in C++. Just pass Test case 6.That is benchmark here :p |
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2017-02-09 03:44:06
Your solution should print first occurrence of target element. Also use scanf and printf in C++ to beat TLE |
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2016-07-08 14:39:05
lower bound giving Wrong dont know y but when implemented on my own gives all A.C |
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2016-04-07 22:34:20
I find the input solution, but my code can't be submited <snip> Last edit: 2023-05-12 09:12:10 |
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2016-02-15 12:53:34 sharif ullah
I think lower_bound() function causes wrong answer |
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2016-02-02 22:12:40
if there is repetition then you need to print the least index as search(2) in 1 2 2 2 2 2 2 2 3 4 25 is 1 |