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BAT3 - BATMAN3 |
Bruce Wayne: I do fear death. I fear dying in here while my city burns.
Blind Prisoner: Then make the climb.
Bruce Wayne: How?
Blind Prisoner: As the child did. Without the rope. Then fear will find you again.
The Epic fight between BANE and BATMAN saw BATMAN on the losing side. Bane delivers a crippling blow to Batman's back, then takes him to a foreign, well-like prison where escape is virtually impossible.
The prison as we know is a place from where no man ever escaped, except for the child of Ra's al Ghul himself.
The heroics of BATMAN saw him escape the prison, however after the prison came the Valleys. To reach the city, He needed to cross these valleys. Meanwhile, BANE's army has surrounded the city and trapped all the policemen underground. Each of these peaks contain exactly one policeman held captive by Bane's men. Since, BATMAN needs to build his own army, he decides to free some of the policemen on his way.
Also BATMAN needed to save his energy before his battle with Bane, so he decided to take only downhill (strictly) jumps. Detective John Blake (now called as ROBIN) is standing in one of these peaks with a mini-BAT. This will allow BATMAN to take a maximum one jump uphill ahead. BATMAN can choose to flee ROBIN and use the BAT or rather cross over without his help.
The task in hand is to maximize the army strength to face BANE as BATMAN crosses over. (BATMAN can take his first jump on any of these peaks)
Bane: So, you came back to die with your city.
Batman: No. I came back to stop you.
Input
t: number of testcases.
n: number of peaks.
m: (zero based) index of the peak where ROBIN is standing.
n integers denoting the height of the peaks.
Output
The maximum strength of the army.
Constraints
1<=n<=1000
Example
Input: 1 6 4 6 3 5 2 4 5 Output: 4
Added by: | Romal Thoppilan |
Date: | 2013-02-06 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | own problem |
hide comments
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2014-02-07 23:59:04 Prashant Khurana
Batman does not need to reach the last peak. |
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2014-01-31 10:42:39 Rishav Goyal
@Ehor index is 0 based index, so Robin is at 4 , not at 2 !! |
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2013-07-09 13:03:13 Romal Thoppilan
- Its mentioned in the problem statement: Batman can take his first jump to any of these peaks (and initially he's not standing on any of these peaks). -He need to the cross the last peak, need not jump on it. |
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2013-07-09 10:36:37 Ujjwal Arora
@Romal Thoppilan, is it necessary to choose first peak, or batman could start from any peak ? for eg. 10 2 6 4 8 7 6 5 4 3 2 1 could batman start from 8 (answer=8) or only from first peak (answer=6) ? Also, what should we print if batman couldn't reach to the last peak, like : 5 1 6 8 7 3 10 is the answer 2 or 0 ? Last edit: 2013-07-09 12:17:25 |
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2013-03-27 06:30:44 Romal Thoppilan
yes! |
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2013-03-18 13:00:59 Witold D³ugosz
"(zero based)index of the peak where ROBIN is standing" means, that in the example Robin is on the peek with height 4. So, constraints on m are m>=0 and m<n. Am I right? Last edit: 2013-03-18 18:10:00 |
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2013-02-16 20:32:49 Romal Thoppilan
1. Batman can surely make any kind of jumps forward with the BAT . 2. Nope , the BAT is too heavy to carry along. |
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2013-02-12 11:47:39 Ehor Nechiporenko
@Romal Thoppilan, could you please clarify some information. Batman could move strictly down, so he cannot move from height 5 to height 5. But when he steps to uses mini-Bat, could he make jump to the same height. And also, when Batman meets mini-Bat, could he use it from another place, or he should jump exactly from the peak m. As example with input 6 3 6 3 5 2 5 4 Can Batmen take mini-Bat from position 3, then jump to peak 2 and only then use mini-Bat to jump to the peak 5 with height 5? |
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2013-02-12 09:50:05 Ehor Nechiporenko
@New AcP: Starts from 6, then moves to 5 (or 3), then moves to 2 (there is the Robin), then uses mini-BAT and flies to 4 or 5, it doesn't matter. |
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2013-02-09 11:49:04 NeW AcP
Can anyone explain me how the output is 4 in the given sample case. Thanks. |