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BAISED - Biased Standings |
Usually, results of competitions are based on the scores of participants. However, we are planning a change for the next year of IPSC. During the registration each team will be able to enter a single positive integer : their preferred place in the ranklist. We would take all these preferences into account, and at the end of the competition we will simply announce a ranklist that would please all of you.
But wait... How would that ranklist look like if it won't be possible to satisfy all the requests?
Suppose that we already have a ranklist. For each team, compute the distance between their preferred place and their place in the ranklist. The sum of these distances will be called the badness of this ranklist.
Problem specification
Given team names and their preferred placements find one ranklist with the minimal possible badness.
Input specification
The first line of the input file contains an integer T specifying the number of test cases. Each test case is preceded by a blank line.
Each test case looks as follows: The first line contains N : the number of teams participating in the competition. Each of the next N lines contains a team name (a string of letters and numbers) and its preferred place (an integer between 1 and N, inclusive). No two team names will be equal.
Output specification
For each of the test cases output a single line with a single integer : the badness of the best ranklist for the given teams.
Example
Input: 2 7 noobz 1 llamas 2 Winn3rz 2 5thwheel 1 NotoricCoders 5 StrangeCase 7 WhoKnows 7 3 ThreeHeadedMonkey 1 MoscowSUx13 1 NeedForSuccess 1 Output: 5 3Explanation:
In the first test case, one possible ranklist with the minimal badness is:
1. noobz 2. llamas 3. Winn3rz 4. 5thwheel 5. NotoricCoders 6. WhoKnows 7. StrangeCase
In the second test case all ranklists are equally good.
Note: the input file will not exceed 5MB.Added by: | Fudan University Problem Setters |
Date: | 2007-12-01 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: C99 ERL JS-RHINO |
Resource: | IPSC 2006 |
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2015-08-13 06:51:07 SangKuan
haha,after 4 wa(forgot memset),my O(n) code got ac. |
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2015-08-13 04:53:06 SangKuan
easy,but use O(nlogn). |
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2015-07-16 09:33:46
There is very small change in time by switching from O(nlnn) to O(n) in Python.... |
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2015-04-15 10:04:23 krish
Easy one:) |
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2015-03-22 19:57:51 ANUJ RATHORE
name of teams let me understanfd SISGEV saga.. |
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2015-03-22 19:57:20 ANUJ RATHORE
my 50th.. |
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2014-09-14 22:01:35 thewatch
tip:: don't use vectors(TLE) they are slow try use normal arrays(AC).. |
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2014-06-04 07:51:21 Neel Jinwala
long long int! >.< |
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2014-06-04 07:19:56 kelaseek
nlogn + n passed |
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2014-01-14 18:25:28 Ankit Jain
quite easy...:) |