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RGB7544 - Утга олголт 4 |
NxN хэмжээтэй квадрат массивыг жишээн дээрх загвараар дүүргэ.
Input
Квадрат массивын хэмжээ натурал тоо N өгөгдөнө. N<10.
Output
Квадрат массивын элементүүдийг мөр мөрөөр нь хэвлэнэ.
Гэхдээ элемент бүрийг 3 хоосон зайд хойш нь шахаж хэвлэнэ. Жишээг сайн ажиглана уу.
Жишээн дээрх 5-ын тоо гэхэд урдаа, хойноо тус бүр 2 хоосон зайтай байна. Мөн 15-ын тоо урдаа, хойноо тус бүр 1 хоосон зайтай байна.
Example
Input: 5
Output: 25 24 23 22 21
20 19 18 17 16
15 14 13 12 11
10 9 8 7 6
5 4 3 2 1
Нэмсэн: | Bataa |
Огноо: | 2013-02-07 |
Хугацааны хязгаарлалт: | 1s |
Эх кодын хэмжээний хязгаарлалт: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Програмчлалын хэлүүд: | ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE |
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2024-05-16 03:50:21
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣠⣤⣄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣀⣀⣀⣀⣀⣀⣀⡴⠋⠀⠀⣸⣩⣀⣀⣀⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢰⠁⢠⣀⡀⠀⠀⢀⡞⣁⣄⠀⢀⣿⣿⣿⣿⣿⣿⣭⡙⢷⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⠀⢸⠇⠉⠙⠒⣾⠋⠀⠀⠃⢸⣿⣿⣿⣿⣿⣿⣿⣿⡎⣇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⡄⣼⠀⠀⠀⣸⠃⠀⠀⠀⠀⣿⣿⣿⣿⣿⣿⠿⢻⣿⣷⢻⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣧⢎⡄⠀⢠⡏⠀⠀⠀⠀⢸⠿⣯⣍⠉⠁⣠⣤⣌⣿⣿⣾⡆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢈⢽⣿⣿⡄⣼⠁⠀⠀⠀⠀⣸⠀⠀⠁⠀⠀⠋⠀⢈⣿⣿⣟⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⠃⠉⠀⡟⠀⠀⠀⠀⠀⡿⣆⣠⡆⢀⠀⡄⢠⡆⣿⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢰⡇⠀⠀⠀⠀⠀⡏⠈⠉⠂⠸⣄⡻⠞⢹⣿⣿⡟⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⠁⠀⠀⠀⠀⢀⡇⢤⣄⣈⣃⣰⠃⢀⣿⣿⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⠀⠀⠀⠀⠀⢸⣧⡀⠑⠭⢝⣩⣴⣿⣿⣿⣿⣸⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⠀⠀⠀⠀⠀⢸⣿⡿⠳⠟⣿⣿⣿⣿⣿⣿⡏⡏⠀⠀⠀⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⠀⠀⠀⠀⠀⢸⣟⣧⡀⠀⢻⣿⣿⣿⣿⠻⢿⠃⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⡀⠀⠀⠀⠀⢸⠹⡼⣿⠦⣄⣙⡿⢿⣿⣇⡟⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠘⣇⠀⠀⠀⠀⠈⠆⣿⡊⠳⣄⠉⠁⢀⠙⣟⡟⢓⣶⣄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠸⢷⣄⠂⠀⠀⠀⢸⡇⣱⢛⡷⣦⣀⡑⣼⣞⣷⣷⣽⣧⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣷⣦⡀⠀⠈⣿⢹⣲⣾⣿⣿⡙⣽⢿⣽⣯⢺⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣶⣄⣿⡜⣼⣿⣿⣷⡷⣝⣼⣿⣯⣿⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⣿⣿⣵⢿⣿⣿⣿⣇⣷⣿⣿⣕⡏⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢿⣿⣿⣿⣿⣿⣿⣿⣿⣻⣿⣿⣟⣦⣗⣟⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⢿⣿⣿⣿⣿⣿⣿⣿⡿⣻⣿⣿⣿⣿⣻⢸⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠙⠿⣿⡝⣻⣿⠏⣩⡾⣿⣿⣿⣿⣿⣾⡆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣵⠟⢷⡲⢆⣿⣿⣿⣿⣿⣟⢤⣣⢷⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⡴⠋⠀⠀⠈⢷⣿⣿⣿⣿⡿⣿⡟⢞⣽⠋⠻⡄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⡾⠋⠀⠀⠀⠀⠀⠸⣿⣿⣿⣿⡇⡿⣟⡾⠁⠀⠀⠙⣆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣰⠋⠀⠀⠀⠀⠀⠀⠀⠀⣯⣿⣿⣿⢋⣼⡾⠁⠀⠀⠀⠀⠘⣆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣼⠁⠀⠀⠀⠀⠀⠀⠠⣀⠀⢹⣿⣹⣿⡗⣼⢁⡤⠂⠀⠀⠀⠀⢸⡄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⠇⠀⠀⠀⠀⠀⠀⠀⠀⠈⠣⣸⢲⣎⣍⣹⡷⠋⠀⠀⠀⠀⠀⠀⠈⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠸⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠘⣏⠉⢹⡏⠀⠀⠀⠀⠀⠀⠀⠀⢠⠇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢹⡂⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢻⡄⢸⡇⠀⠀⠀⠀⠀⠀⠀⠀⢸⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠻⡄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣷⢸⡇⠀⠀⠀⠀⠀⠀⠀⠀⡞⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠙⣦⠀⠀⠀⠀⠀⠀⠀⠀⠀⠸⣿⠇⠀⠀⠀⠀⠀⠀⠀⣼⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⢧⡀⠀⠀⠀⠀⠀⠀⠀⠀⢿⡅⠀⠀⠀⠀⠀⠀⣼⠃⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠻⣄⠀⠀⠀⠀⠀⠀⠀⢸⡇⠀⠀⠀⠀⠀⣸⠃⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠘⢳⡀⠀⠀⠀⠀⠀⠀⣧⠀⠀⠀⠀⡔⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ |
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2024-02-14 05:31:41
whahdefah |
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2023-01-09 08:40:35
ika giin bololgiig huularay #include<stdio.h> #include<math.h> main() { int i,n,j,t,a[100][100]; scanf("%d",&n); t=1; for (i=n-1;i>=0;i--) { for(j=n-1; j>=0 ;j--) {a[i][j]=t; t++;}} for(i=0; i<n; i++) { for(j=0; j<n ;j++) printf("%3d",a[i][j]); printf("\n"); } } |
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2022-10-24 06:32:29
#include<iostream> using namespace std; main(){ int n,i,j,s=1,a[101][101]={0}; cin>>n; for(i=1; i<=n; i++) { for(j=1; j<=n; j++) { if(i%2==1) {a[i][j]=i*n-j+1;} else {a[i][j]=(i-1)*n+j;} } } for(i=1; i<=n; i++) { for(j=1; j<=n; j++) { cout<<a[i][j]<<" "; } cout<<endl; } } |
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2022-10-12 05:47:48
#include<cstdlib> #include<iostream> using namespace std; main() { int a[100][100],b,c,d,e,n,i,s; cin>>n; for(i=n*n; i>=1; i--) { if(i<10) cout<<" "<<" "<<i; if(i>=10) cout<<" "<<i; if(i%n==1) cout<<endl; } system("pause"); } |
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2020-01-21 08:28:07
#include <iostream> using namespace std; int main(){ long long n,m,a,s,l,p; cin>>n; s=n*n; for(int i=1;n>=i;i++){ for(int j=1;j<=n;j++){ if(s<=9) cout<<" "<<s; else cout<<" "<<s; s--; } cout<<endl; } return 0; } |
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2020-01-07 07:15:20
#include<bits/stdc++.h> using namespace std; int main(){ long long n,m,i,a,j,s,l,p; cin>>n; s=n*n; for(i=1; n>=i; i++){ for(j=1; j<=n; j++){ if(s<=9) cout<<" "<<s; else cout<<" "<<s; s--; } cout<<endl; } return 0; } |
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2019-11-16 06:07:42
#include<cstdio> int main () { int n, i, j; scanf ("%d",&n); for(i = 1; i <= n; i++) { if(i%2!=0)for(j = (i-1)*n+1; j <= n*i; j++) { printf(" %d", j); } else for(j = n*i; j >= (i-1)*n+1; j--) { printf(" %d", j); } printf("\n"); } return 0; |
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2019-11-16 06:01:54
code tabihaa boli |
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2019-05-06 11:10:23
#include<bits/stdc++.h> using namespace std; main() { int a[100][100],c,d,s=0,i,n; cin>>n; for(i=n*n;i>=1;i--) { if(i<10) cout<<' '<<' '<<i; if(i>=10) cout<<' '<<i; if(i%n==1) cout<<endl;} //system("pause"); return 0; } |