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RGB7316 - Гурван тооны ХБЕХ |
Өгөгдсөн 3 натурал тооны хамгийн бага ерөнхий хуваагдагчийг (ХБЕХ) ол.
Input
Нэг мөрөнд 3 натурал тоо зайгаар тусгаарлагдан өгөгдөнө. Тоонууд 1200-аас ихгүй.
Output
ХБЕХ
Example
Input:
4 6 18
Output:
36
| Нэмсэн: | Bataa |
| Огноо: | 2013-01-14 |
| Хугацааны хязгаарлалт: | 1s |
| Эх кодын хэмжээний хязгаарлалт: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Програмчлалын хэлүүд: | ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE |
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2024-02-04 13:08:53
Chipi chipi chapa chapa Dubi dubi daba daba Mágico mi dubi dubi Boom, boom, boom, boom Chipi chipi chapa chapa Dubi dubi daba daba Mágico mi dubi dubi Booooooooooom |
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2024-01-31 02:13:44
chipi chipi chapa chapa rubi rubi raba raba wo xihuang bing chilling |
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2024-01-16 06:10:28
#include <bits/stdc++.h> using namespace std; int main (){ int a, b, c, x, ans; cin >> a >> b >> c; x = a * b / __gcd(a, b); ans = c * x / __gcd(c, x); cout << ans << endl; return 0; } //a*b = hieh(a, b) * hbeh(a, b) |
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2023-12-27 15:23:24
int a,b,c; cin>>a>>b>>c; int result = 1; int i=2; while(i<=a||i<=b||i<=c){ if(a%i==0||b%i==0||c%i==0){ result = result * i; //2 if(a%i==0) a=a/i;//2 if(b%i==0) b=b/i;//3 if(c%i==0) c=c/i;//9 }else{ i=i+1; } } cout << result; return 0; |
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2023-11-20 12:38:43
dwhgjhgfuufsgygfagsyguyagsgfhgyysgasg hi guy woolcome to my histrory irs s## lol f#rc# its so bab histoyire |
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2023-11-04 11:23:16
#include <iostream> using namespace std; int main() { int a, b, c, min; cin >> a >> b >> c; min = a; if(min > b) min = b; if(min > c) min = c; for(int i = min ; i <= a * b * c ; i++) { if(i % a == 0 && i % b == 0 && i % c == 0) { cout << i; break; } } } |
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2023-10-20 20:00:25
#include <stdio.h> int fun_1(int a, int b) { while (b != 0) { int temp = b; b = a % b; a = temp; } return a; } int fun_2(int a, int b) { return (a * b) / fun_1(a, b); } int main() { int a, b, c, res; scanf("%d %d %d", &a, &b, &c); int res1 = fun_2(a, b); int res2 = fun_2(res1, c); printf("%d", res2); return 0; } ene shig bodson hun algo |
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2023-09-26 08:53:32
LOL Last edit: 2023-09-26 08:53:56 |
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2023-08-19 22:46:23
hope someone willl publish it >:) Last edit: 2023-08-19 22:47:25 |
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2023-05-10 11:48:04
hi no code here >:) bro i said no code here BRO STOP SCROLLING I SAID STOP ALR HERE IS THE CODE HAHA SIKE L BOZO |
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