Problem hidden
|This problem was hidden by Editorial Board member probably because it has incorrect language|version or invalid test data, or description of the problem is not clear.|

RGB7314 - ХБЕХ

Өгөгдсөн хоёр натурал тооны хамгийн бага ерөнхий хуваагдагчийг ол.

Input

Нэг мөрөнд хоёр натурал тоо зайгаар тусгаарлагдан өгөгдөнө.

Output

ХБЕХ

Example

Input:
9 15

Output:
45

Нэмсэн:Bataa
Огноо:2013-01-11
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2024-12-10 05:35:34
import math
a, b = map(int, input().split())
lcm = (a * b) // math.gcd(a, b)
print(lcm)
2024-09-10 02:50:46
#include<stdio.h>
int main()
{
int n,m,s;
scanf("%d %d",&n,&m);
s=n;
while(true)
{
if(s%n==0 && s%m==0) break;
s++;
}
printf("%d",s);
system("pause");
return 0;
}

2024-08-18 06:28:59
#include<bits/stdc++.h>
using namespace std;
long long a,b,c,d,e,f,x,y,z,w,s,k;
signed main () {
cin>>a>>b;
c=a;
d=b;
while(a>0 && b>0) {
if (a>b) a=a%b;
else b=b%a;
}
if (a==0) cout<<(c*d)/b;
else cout<<(c*d)/a;
}
}huul2
2024-07-18 14:29:13
#include <stdio.h>

main(){
int n, m, n1, m1, t;
scanf("%d%d", &n, &m);
n1 = n;
m1 = m;
while(n != m){
if(n > m){
n = n - m;
}
else{
m = m - n;
}
}
n1 = n1 / n;
m1 = m1 / n;
t = n1 * n * m1;
printf("%d", t);
}
2024-06-05 07:57:42
▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓




2024-04-15 06:53:44
sup neggas
Leave a Comment
|Notes:|
1. Don't post any source code here.|
2. Please be careful, leave short comments only. Don't spam here.|
3. For more discussion (hints, ideas, solutions) please visit our forum.|
4. Authors are allowed to delete the post and use html code here (e.g. to provide some useful links).|
About SPOJ RSS
2024-05-20 03:44:33
▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓
2024-05-09 04:26:22
#include <iostream>
#include <sstream>
#include <string>
#include <cstdlib>
#include <cmath>

using namespace std;

// Headers
string toString (double);
int toInt (string);
double toDouble (string);

int main() {
int davhar, ail, toot, x, y;

cin >> davhar;
cin >> ail;
cin >> toot;
if (toot % ail == 0) {
x = (int) ((double) toot / ail);
y = ail;
} else {
x = (int) ((double) toot / ail + 1);
y = toot % ail;
}
cout << x << endl;
cout << y << endl;
return 0;
}

// The following implements type conversion functions.
string toString (double value) { //int also
stringstream temp;
temp << value;
return temp.str();
}

int toInt (string text) {
return atoi(text.c_str());
}

double toDouble (string text) {
return atof(text.c_str());
}
2024-05-03 06:59:14
▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓▒▓▓▓
2024-05-02 03:49:28
h

Last edit: 2024-05-02 04:01:03
2024-05-01 08:34:02
pls give me code
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.