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RGB7312 - Тооны факториал

Өгөгдсөн тоо ямар нэгэн тооны факториал бол тэр тоог хэвлэ. Үгүй бол No гэж хэвлэ.

Input

Бүхэл тоо өгөгдөнө.

Output

Өгөгдсөн тоо ямар нэгэн тооны факториал бол тэр тоог үгүй бол No.

Example

Input 1:
24

Output 1:
4
Input 2:
10
Output 2:
No
Input 2:
1 Output 2: 1


Нэмсэн:Bataa
Огноо:2013-01-11
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2023-09-22 03:20:38
uliralaa bod
2023-09-22 03:20:16
munkhuu suga
2023-07-12 14:30:30
#include<iostream>
using namespace std;
int main(){
int n,a=1;
//tsogto mu pyzd
bool l;
cin>>n;
l=0;
for(int i=1;i<=n;i++){
a*=i;
if(a==n){
l = true;
cout<<i;
break;
}
else{
l = false;
}
}
if( l == false )
cout<<"No";
return 0;
}
2023-06-14 04:06:38
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2023-06-13 13:44:23
#include <iostream>
using namespace std;
int main()
{
int n, i = 1, f = 1;
cin >> n;
while(f < n)
{
f *= i;
i++;
}
if(f == n)
{
if(n == 1)
{
cout << 1;
}
else
{
cout << i - 1;
}
}
else
{
cout << "No";
}

return 0;
}
2023-03-15 03:43:30
#include<bits/stdc++.h>
using namespace std;
int main(){
int n,a,b,c,i;
cin>>n;
a=0;
b=n;
for( i=1;i<=20;i++){
if(n%i==0){
a++;
n=n/i;
}
else {
if (n==1)
cout << a;
else cout <<"No";
return 0;
}
}
cout << a ;

return 0;
}
huln nie d zoriulav
mala
2023-03-13 03:05:01
#include<iostream>
using namespace std;
int main(){
int n,a=1;
//tsogto mu pyzd
bool l;
cin>>n;
l=0;
for(int i=1;i<=n;i++){
a*=i;
if(a==n){
l = true;
cout<<i;
break;
}
else{
l = false;
}
}
if( l == false )
cout<<"No";
return 0;
}
2023-03-01 04:10:23
уллл0

2023-02-17 05:57:48
#include<bits/stdc++.h>
using namespace std;

int main()
{
int m, n, b, i;
scanf("%d" ,&n);

m=0;
b=n;

for(i=1; i<=10000; i++)
{

if(n%i==0)
{
m++;
n=n/i;
}

else
if(n==1)

{
printf("%d" ,m);
break;}

else
{printf("No");
break;}

}

return 0;
}
2023-02-17 01:15:15
#include <stdio.h>

int main(int argc, char** argv) {
int n, x, l, k=1;
scanf("%d", &n);
l=n/2;
for(int m=1;m<l;m++){
k=k*m;
x=m;
if(k==n){
printf("%d", x);
return 0;

}
}
printf("NO");



}
SDOLZ
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