| Бодолт илгээх | Бүх бодолтууд | Шилдэг бодолтууд | Жагсаалт руу буцах |
RGB7232 - Синус нийлбэр 3 |
sinx+sin(sinx)+sin(sin(sinx))+...+sin(sin...sin(sinx)...) нийлбэрийг ол.
Input
Бодит тоо x натурал тоо n нэг мөрөнд нэг зайгаар тусгаарлагдан өгөгдөнө.
Output
Нийлбэр. Таслалаас хойш 3 орны нарийвчлалтайгаар гарга.
Example
Input: 1.0 3 Output: 2.266
| Нэмсэн: | Bataa |
| Огноо: | 2013-01-23 |
| Хугацааны хязгаарлалт: | 1s |
| Эх кодын хэмжээний хязгаарлалт: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Програмчлалын хэлүүд: | ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE |
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2022-01-17 15:31:13
#include<bits/stdc++.h> #include<math.h> using namespace std; int main(){ int n; double x,a,m; cin>>a>>n; x=a; for(int i=1;i<=n;i++){ x=sin(x); m=m+x; } cout<<fixed<<setprecision(3)<<m; return 0; } |
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2020-11-02 11:07:13
ewakoda ich |
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2020-06-01 07:39:25
Last edit: 2020-06-03 04:54:06 |
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2020-03-23 12:53:22
#include<stdio.h> #include<stdlib.h> #include<math.h> int main() { int a , n , i; double x; scanf("%lf%d",&x , &n); double sum=sin(x); double l; l=x; for(i = 1 ; i <n ; i++){ l=sin(l); sum = sum + sin(l); } printf("%.3lf" , sum ); return 0; } =========================good&&luck=========================== Last edit: 2020-03-23 12:55:20 |
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2019-11-23 14:11:34
#include <iostream> #include<math.h> using namespace std; main() { float a,c,s=0,e,i,d=0; int b; cin>>a>>b; e=a; for(i=1;i<=b;i++) { e=sin(e); d=d+e; } cout.setf(ios::fixed); cout.precision(3); cout<<d<<endl; } EZ |
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2019-11-14 13:28:12
mia ene bodolt ni door baigaa goridsonii chini garz sug mine huulhaa boliod uuruu bod |
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2019-11-02 05:53:57
....... : : : : lol ....... |
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2019-11-02 05:51:00
:D |
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2019-11-02 05:50:28
time for big comment |
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2019-11-02 05:49:55
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