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RGB7230 - Синус нийлбэр 1 |
sin(x)+sin(x2)+sin(x3)+...+sin(xn) нийлбэрийг ол.
Input
Бодит тоо x, натурал тоо n зайгаар тусгаарлагдан нэг мөрөнд өгөгдөнө.
Output
Нийлбэр. Таслалаас хойш 3 орны нарийвчлалтай гарга.
Example
Input: 2.5 3 Output: 0.648
Нэмсэн: | Bataa |
Огноо: | 2013-01-23 |
Хугацааны хязгаарлалт: | 1s |
Эх кодын хэмжээний хязгаарлалт: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Програмчлалын хэлүүд: | ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE |
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2022-09-22 08:27:32
Scanner scan = new Scanner(System.in); System.out.print(""); double nu1 = scan.nextDouble(); System.out.print(""); double nu2 = scan.nextDouble(); double a=0; for(int i=1;i<=nu2;i++) { a+=Math.sin(Math.pow(nu1, i)); } System.out.printf("%.3f",+a); |
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2022-06-17 16:18:51
#include<bits/stdc++.h> using namespace std; int main() { double a,r=0; int b; cin>>a>>b; for(int i=1; i<=b; i++) { r+=sin(pow(a, i)); } cout<<fixed<<setprecision(3)<<r; return 0; } |
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2022-06-02 02:55:00
uher mongol |
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2022-05-20 06:24:36
shut the fuck up or I will kick your ass right now and right here, son of a bitch. |
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2022-01-23 09:59:12
#include<stdio.h> #include<math.h> #include<stdlib.h> float a,b,c,d=0,k; int main() { scanf("%f %f",&a,&k); for(c=1; c<=k; c++) { b=sin(pow(a,c)); d=d+b; } printf("%.3f",d); } dahiad tugsuu ah ni bn aa kkk |
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2021-11-28 17:21:12
you are looking at this comment because you're stuck or you're just being lazy. If you copy now, you will copy again and again and again. any thoughts? so stop copying and do it, or ask for some help. |
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2021-01-18 15:20:39
I have tried to solve this problem by using simple recursion but kept receiving the wrong answer. Check out #include <iostream> #include <cmath> using namespace std; double sinus(double a, int n){ if(n == 1) return sin(a); if(n == 0) return 0; return sin(pow(a, n)) + sinus(a, (n - 1)); } int main(){ double a; int n; cin >> a >> n; cout.setf(ios::fixed); cout.precision(3); double res = sinus(a, n); cout << res; return 0; } Dear Corpse XD |
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2020-10-14 12:08:44
Hmmmmmmmmmm |
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2020-01-21 07:54:05
#include <iostream> #include <cmath> using namespace std; int main(){ int a,n; double x,sum=0,I=1; cin>>x>>n; for(int i=1;i<=n;i++){ I*=x; sum+=sin(I); } cout.setf(ios::fixed); cout.precision(3); cout<<sum<<endl; return 0; } |
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2019-11-02 06:33:04
#include <cstdio> #include <cmath> int main () { int a , n , i; double x; scanf("%lf%d",&x , &n); double sum = 0; double l = 1; for(i = 1 ; i <= n ; i++){ l = l * x; sum = sum + sin(l); } printf("%.3lf" , sum ); } SUPER |