Problem hidden
|This problem was hidden by Editorial Board member probably because it has incorrect language|version or invalid test data, or description of the problem is not clear.|

RGB7211 - Тооны зэргийн хүрд

a тооны n хүртэлх зэрэгтүүдийг жишээн дээрх хэлбэрээр хэвлэ.

Input

a, n натурал тоонууд нэг мөрөнд нэг зайгаар тусгаарлагдан өгөгдөнө. (a,n<10)

Output

Зэргийн хүрдийг хэвлэ.

Example

Input:
3 5

Output:
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243

Нэмсэн:Bataa
Огноо:2011-06-21
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2024-12-09 03:42:33
jhuhuhiuuhuh
2024-11-26 18:38:56
#include<iostream>
using namespace std;
int main()
{
int a,b,c,d,s=1,t,i,n;
cin>>a>>n;
for(i=1;i<=n;i++){
s*=a;
cout<<a<<"^"<<i<<"="<<s<<endl;
}

}//ryuu bol gicii
2024-11-16 05:35:36
#include<iostream>
using namespace std;
int main() {
int n,a,u,i = 1;
cin>>n>>a;
for(u=1;u<=a;u++){
i = i * n;
cout << n <<"^" << u <<"=" <<i <<endl<<endl;

}
} //huul teneg boovni usnuudee
2024-10-31 04:10:34
⢰⡿⠋⠁⠀⠀⠈⠉⠙⠻⣷⣄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⢀⣿⠇⠀⢀⣴⣶⡾⠿⠿⠿⢿⣿⣦⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⣀⣀⣸⡿⠀⠀⢸⣿⣇⠀⠀⠀⠀⠀⠀⠙⣷⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⣾⡟⠛⣿⡇⠀⠀⢸⣿⣿⣷⣤⣤⣤⣤⣶⣶⣿⠇⠀⠀⠀⠀⠀⠀⠀⣀⠀⠀
⢀⣿⠀⢀⣿⡇⠀⠀⠀⠻⢿⣿⣿⣿⣿⣿⠿⣿⡏⠀⠀⠀⠀⢴⣶⣶⣿⣿⣿⣆
⢸⣿⠀⢸⣿⡇⠀⠀⠀⠀⠀⠈⠉⠁⠀⠀⠀⣿⡇⣀⣠⣴⣾⣮⣝⠿⠿⠿⣻⡟
⢸⣿⠀⠘⣿⡇⠀⠀⠀⠀⠀⠀⠀⣠⣶⣾⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⠁⠉⠀
⠸⣿⠀⠀⣿⡇⠀⠀⠀⠀⠀⣠⣾⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⠟⠉⠀⠀⠀⠀
⠀⠻⣷⣶⣿⣇⠀⠀⠀⢠⣼⣿⣿⣿⣿⣿⣿⣿⣛⣛⣻⠉⠁⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⢸⣿⠀⠀⠀⢸⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⢸⣿⣀⣀⣀⣼⡿⢿⣿⣿⣿⣿⣿⡿⣿⣿⡿⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠙⠛⠛⠛⠋⠁⠀⠙⠻⠿⠟⠋⠑⠛⠋⠀
2024-10-14 11:41:01
blackperson213cbzd.aternos.me
2024-10-13 16:21:24
Hiij cadahgvi baivl holbogdoj tuslamj awj bolno
IG: ratitulation8
2024-10-13 16:20:31
I love you<3
2024-09-18 04:34:26
public class BankAccount {
private String accountNumber;
private double balance;

// Constructor to initialize the account number and optional balance
public BankAccount(String accountNumber, double initialBalance) {
this.accountNumber = accountNumber;
this.balance = initialBalance;
}

// Method to deposit money into the account
public void deposit(double amount) {
if (amount > 0) {
balance += amount;
System.out.println("Deposited: $" + amount);
} else {
System.out.println("Deposit amount must be positive.");
}
}

// Method to withdraw money from the account
public void withdraw(double amount) {
if (amount > 0 && amount <= balance) {
balance -= amount;
System.out.println("Withdrew: $" + amount);
} else {
System.out.println("Insufficient funds or invalid amount.");
}
}

// Method to check the account balance
public double checkBalance() {
return balance;
}

// Method to transfer money to another BankAccount
public void transfer(BankAccount targetAccount, double amount) {
if (amount > 0 && amount <= balance) {
withdraw(amount);
targetAccount.deposit(amount);
System.out.println("Transferred: $" + amount + " to account: " + targetAccount.getAccountNumber());
} else {
System.out.println("Insufficient funds or invalid amount.");
}
}

// Getter for account number
public String getAccountNumber() {
return accountNumber;
}

// Optional: To get a string representation of the account
@Override
public String toString() {
return "Account Number: " + accountNumber + ", Balance: $" + balance;
}
}
2024-05-10 04:51:43
#include <bits/stdc++.h>
using namespace std;

int main() {

int a,n,c=1;
scanf("%d%d",&a,&n);
for(int i=1; i<=n; i++){
for(int b=0; b<i; b++){
c*=a;
}
printf("%d^%d=%d\n", a, i, c);
c=1;
}
}
2024-05-10 04:50:08
#include <bits/stdc++.h>
using namespace std;

int main() {

int a,n,c=1;
scanf("%d%d",&a,&n);
for(int i=1; i<=n; i++){
for(int b=0; b<i; b++){
c*=a;
}
printf("%d^%d=%d\n", a, i, c);
c=1;
}
}
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.