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RGB7114 - Тэгш тоонууд YES

Гурван тоо өгөгдөнө. Тоо тэгш бол YES үгүй бол NO гэж хэвлэ.

Input

Int төрлийн 3 тоо нэг нэг мөрөнд өгөгдөнө.

Output

Тоо тус бүрийг шалгаад нэг нэг мөрөнд хариуг хэвлэ.

Example

Input:
3
4
5
Output:
NO
YES
NO


Нэмсэн:Bataa
Огноо:2011-05-31
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

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2023-11-21 07:48:26



































































































































































































































































































































































































































































2023-11-21 07:25:57 (


































































































































































































































































































































































































































































2023-11-21 07:25:57 (


































































































































































































































































































































































































































































2023-11-21 07:25:57 (
2023-11-03 05:58:38
sssss
2023-10-20 13:29:25
hulha boli malaa
2023-10-10 06:05:44
ene hurtel irsend bayr hurgiii odoo buuj ogojhgu bol amidralgu bollo shutisiin arhicidaa
2023-05-29 07:09:12
#include <iostream>
using namespace std;

int main() {
int a, s, c;
cin>>a>>s>>c;
if(a%2==0){
cout<<"YES"<<endl;
}
else{
cout<<"NO"<<endl;
}
if(s%2==0){
cout<<"YES"<<endl;
}
else{
cout<<"NO"<<endl;
}
if(c%2==0){
cout<<"YES"<<endl;
}
else{
cout<<"NO"<<endl;
}
return 0;
}
2023-04-05 07:41:01
#include <iostream>
using namespace std;

int main() {

int a,b,c;
cin>>a>>b>>c;

if (a%2==0)
cout<<"YES\n";
else
cout<<"NO\n";

if (b%2==0)
cout<<"YES\n";
else
cout<<"NO\n";

if (c%2==0)
cout<<"YES\n";
else
cout<<"NO\n";


return 0;
}
2023-04-05 07:39:34
#include <iostream>
using namespace std;

int main() {

int a,b,c;
cin>>a>>b>>c;

if (a%2==0)
cout<<"YES\n";
else
cout<<"NO\n";

if (b%2==0)
cout<<"YES\n";
else
cout<<"NO\n";

if (c%2==0)
cout<<"YES\n";
else
cout<<"NO\n";


return 0;
}
2023-04-05 07:38:16
#include<bits/stdc++.h>
using namespace std;
int main () {
int a,b,c,d,e,f,g;
cin>>a>>b>>c;
if(a%2==0){
cout<<"YES\n";
}else
cout<<"NO\n";

if(b%2==0)
cout<<"YES\n";
}else
cout<<"NO\n";
if
(c%2==0)
cout<<"YES\n";
}else
cout<<"NO\n";

}
2023-01-17 15:05:04
a=int(input())
b=int(input())
c=int(input())
if(a%10%2==0):
print("YES")
else:
print("NO")
if(b%10%2==0):
print("YES")
else:
print("NO")
if(c%10%2==0):
print("YES")
else:
print("NO")
Delgerekh^^
2022-12-21 17:59:19
#include <stdio.h>
char * wether(int x){
if(x%2 == 0){
return "YES";
}else{
return "NO";
}
}
int main(void) {
// your code here
int a,b,c;
scanf("%d%d%d",&a,&b,&c);
char* f = wether(a);
char* s = wether(b);
char* t = wether(c);
printf("%s\n%s\n%s",f,s,t);
return 0;
}
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