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RGB7111 - 11-д хуваагддаггүй

Өгөгдсөн 4 тооны 11-д хууваагддаггүй тоонуудынх нь нийлбэрийг ол. 

Input

Нэг мөрөнд Int төрлийн 4 тоо зайгаар тусгаарлагдан өгөгдөнө.

Output

11-д хуваагддаггүй тоонуудын нийлбэр.

Example

Input:
7 22 13 30

Output:
50

Нэмсэн:Bataa
Огноо:2011-05-27
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2025-03-15 10:22:02
huuldaguud n gomo
huuldaguud n gomo
huuldaguud n gomo
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huuldaguud n gomo
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huuldaguud n gomo
huuldaguud n gomo
huuldaguud n gomo


2025-03-15 08:47:46
#include <iostream>
using namespace std;

int main()
{
int a,b,c,d,e=0,f,g,h,i;
cin>>a>>b>>c>>d;
if(a%11!=0){
e=e+a;
}
if(b%11!=0){
e=e+b;
}
if(c%11!=0){
e=e+c;
}
if(d%11!=0){
e=e+d;
}

cout<<e;
return 0;
}
byrlj yvrai guilgcnmn(gambaabsh)
2025-02-19 10:58:16
SOYOLGYI YASAN BUDUULEG VM VE
2024-12-02 08:54:58
shaaaaaaaaaaaaaaaaaaaaa gsh
2024-11-11 08:14:35
#include <iostream>
using namespace std;

int main() {

int size = 4, a[size], sum = 0;
for(int i = 0; i<size; i++){
scanf("%d",&a[i]);
if(a[i]%11>0){
sum+=a[i];
}
}
printf("%d",sum);
}
huul minii duu byan daaj amidaraarai

Last edit: 2024-11-11 08:15:22
2024-10-22 12:21:50
#include <iostream>
using namespace std;

int main() {

int size = 4, a[size], sum = 0;
for(int i = 0; i<size; i++){
scanf("%d",&a[i]);
if(a[i]%11>0){
sum+=a[i];
}
}
printf("%d",sum);
}
huul
2024-10-21 12:22:25
#include <iostream>
using namespace std;

int main()
{
int a,b,c,d,e=0,f,g,h,i;
cin>>a>>b>>c>>d;
if(a%11!=0){
e=e+a;
}
if(b%11!=0){
e=e+b;
}
if(c%11!=0){
e=e+c;
}
if(d%11!=0){
e=e+d;
}

cout<<e;
return 0;
}
byrlj yvrai guilgcnmn(gambaabsh)
2024-08-01 13:34:58
#include <iostream>
using namespace std;

int main() {

int size = 4, a[size], sum = 0;
for(int i = 0; i<size; i++){
scanf("%d",&a[i]);
if(a[i]%11>0){
sum+=a[i];
}
}
printf("%d",sum);
}
2024-06-19 11:17:29
half life ? ..Why not the full one
2024-05-19 09:11:57
#include<stdio.h>
main(){
int a,b,c,d,sum=0;
scanf("%d%d%d%d",&a,&b,&c,&d);
if(a%11!=0)sum=sum+a;
if(b%11!=0)sum=sum+b;
if(c%11!=0)sum=sum+c;
if(d%11!=0)sum=sum+d;
printf("%d",sum);
}
buyn dj yvre
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