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RGB7109 - Тэнцүү 5

Өгөгдсөн 3 тоон дотроос 5-тай тэнцүү тоонуудын тоог ол.

Input

Нэг мөрөнд Int төрлийн 3 тоо зайгаар тусгаарлагдан өгөгдөнө.

Output

5-тай тэнцүү тоонуудын тоо.

Example

Input:
2 5 5

Output:
2

Нэмсэн:Bataa
Огноо:2011-05-26
Хугацааны хязгаарлалт:0.200s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2021-12-04 04:23:22
fuck
2021-10-17 05:42:50
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int count = 0;
int[] arr = new int[3];
for(int i = 0; i < 3; i++) {
arr[i] = sc.nextInt();
}
for(int i : arr) {
if (i == 5) {
count++;
}
}
System.out.println(count);
}
2021-10-12 13:32:41
import statistics
import math
lst=input().split()
integer_list=[]
for x in lst:
integer_list.append(int(x))
mode = statistics.mode(integer_list)
integer_list.count(mode)
2021-09-10 06:37:35
tng barsa
2020-10-21 10:31:32
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,b,c,s=0;
cin>>a>>b>>c;
if(a==5) s=s+1;
else if(a<5 && a>5) s=s+0;
if(b==5) s=s+1;
else if(b<5 && b>5) s=s+0;
if(c==5) s=s+1;
else if(c<5 && c>5) s=s+0;
cout<<s;
return 0;
} altaik bnooo sugudaa
2020-08-05 06:38:17
huulhaa boli ez chdeee??????????
2019-10-09 13:06:22
#include <cstdio>
using namespace std;
int main(){
int a, b, c, d;
scanf("%d%d%d",&a,&b,&c);
d = 0;
if(a==5) d=d+1;
if(b==5) d=d+1;
if(c==5) d=d+1;
printf("%d",d);
}
2019-10-06 08:46:06
#include <iostream>
using namespace std;
main()
{
int a,b,c,d;
cin>>a>>b>>c;
d=0;
if (a==5) d=d+1;
if (b==5) d=d+1;
if (c==5) d=d+1;
cout<<d;
}
2019-09-29 07:43:04
i dont understand :(:(:(:(:(:(:( pls somebody help :(:(:(:(:(:(
2019-07-04 12:00:39
eniiig davtaltaar bodson hun bnuu? esvel davhar nohtsol shalgah c ymuu syntax iig ni martcihjee
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