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RGB7108 - Сондгой тоонуудын үржвэр |
Өгөгдсөн 3 тоон дахь сондгой тоонуудын үржвэрийг ол. Ядаж 1 сондгой тоо байгаа.
Input
Нэг мөрөнд Int төрлийн 3 тоо зайгаар тусгаарлагдан өгөгдөнө.
Output
Үржвэр
Example
Input: 5 2 3 Output: 15
Нэмсэн: | Bataa |
Огноо: | 2011-05-24 |
Хугацааны хязгаарлалт: | 1s |
Эх кодын хэмжээний хязгаарлалт: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Програмчлалын хэлүүд: | ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE |
hide comments
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2022-03-24 01:52:48
#include <stdio.h> int main () { int a,b,c,d,f=1; scanf("%d %d %d",&a,&b,&c ); if(a%2>0) { f=f*a; } if(b%2>0) { f=f*b; } if(c%2>0) { f=f*c; } printf("%d", f); } amjilt psdakuda |
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2022-03-10 05:45:47
l |
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2021-12-11 11:58:36
a,b,c = [int(x)for x in input().split()] s = 1 if a%2==1: s = s * a if b%2==1: s = s * b if c%2==1: s = s * c print(str(s)) |
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2021-10-04 12:56:24
cap |
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2021-09-20 09:52:17
#include <iostream> using namespace std; int main() { int a, b, c, d = 1; cin >> a >> b >> c; if ( a % 2 == 1 ){ d=d * a; } if ( b % 2 == 1 ){ d=d*b } if ( c % 2 == 1 ){ d=d*c } cout << d <<endl; return 0; } Dulguun |
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2021-08-04 11:23:58
hey u stop |
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2021-03-03 07:48:00
#include <stdio.h> int main () { int a,b,c,d,f=1; scanf("%d %d %d",&a,&b,&c ); if(a%2>0) { f=f*a; } if(b%2>0) { f=f*b; } if(c%2>0) { f=f*c; } printf("%d", f); } bat |
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2020-11-08 12:32:06
#include<stdio.h>; main() { int a,b,c; int f=1; scanf("%d %d %d", &a, &b, &c); if((a+1)%2==0) f=f*a ; if((b+1)%2==0) f=f*b; if((c+1)%2==0) f=f*c; printf("%d",f); return 0; } hylbar bodolt |
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2020-11-04 09:05:01
#include<bits/stdc++.h> using namespace std; long long a,d,f,g; int main() { cin>>a>>d>>f; if(a%2>0) a=a; else a=1; if(d%2>0) d=d; else d=1; if(f%2>0) f=f; else f=1; g=a*d*f; cout<<g; return 0; } |
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2020-08-05 09:48:53
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