| Бодолт илгээх | Бүх бодолтууд | Шилдэг бодолтууд | Жагсаалт руу буцах |
RGB7002 - Гурвалжин |
Өгөгдсөн гурвалжны периметрийг ол.
Input
Гурвалжны талууд бүхэл тоогоор нэг мөрөнд зайгаар тусгаарлагдан өгөгдөнө.
Output
Гурвалжны периметр.
Example
Input:
3 4 5
Output:
12
| Нэмсэн: | Bataa |
| Огноо: | 2011-01-15 |
| Хугацааны хязгаарлалт: | 1s |
| Эх кодын хэмжээний хязгаарлалт: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Програмчлалын хэлүүд: | ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE |
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2025-01-14 14:30:20
https://s.team/p/fvrn-rgmc/qbdjnrkb\ |
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2025-01-04 07:43:10
#include <bits/stdc++.h> #define ll long long using namespace std; int main() { int n, k; cin >> n >> k; vector<ll> a(n + 1); for (int i = 0; i < n; i++) { cin >> a[i]; } double l = 0, r = 1e8; int s = 0; for (int i = 0; i < 100; i++){ double m = (l + r) / 2; s = 0; for (int i = 0; i < n; i++) { s += (int) a[i] / m; } if (s >= k) { l = m; }else { r = m; } } cout << l << endl; return 0; } |
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2024-12-13 06:41:30
https://play.typeracer.com?rt=tskq4mu15 |
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2024-12-12 08:51:53
https://play.typeracer.com?rt=gsrebewnd |
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2024-12-10 08:00:36
#include <stdio.h> int main() { int a,b,c,p; scanf("%d %d %d",&a,&b,&c); p=a+b+c; printf("%d",p); return 0; } mai anda |
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2024-12-10 04:45:53
zl\ z;z;xSLC<lda f |
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2024-12-10 02:00:10
Last edit: 2024-12-10 02:04:37 |
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2024-12-10 01:56:41
#include <iostream> using namespace std; int main() { int a,b,c; int perimeter; cin>>a>>b>>c; perimeter=a+b+c; cout<<perimeter; return 0; } |
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2024-12-10 01:21:29
#include<bits/stdc++.h> int main() { int n; scanf("%d", &n); for (int i = 1; i <= n; i++) { if (n % i == 0) { printf("%d ", i); } } return 0; } |
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2024-12-06 08:20:15
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